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Alla [95]
3 years ago
12

Why does The human population continue to grow exponentially

Physics
2 answers:
svlad2 [7]3 years ago
6 0
Global human population growth is around 75 million annually, or 1.1% per year. The global population has grown from 1 billion in 1800 to 7 billion in 2012. Globally, the growth rate of the human population has been declining since 1962 and 1963, when it was 2.20% per annum. In 2009, the estimated annual growth rate was 1.1%. The CIA World Factbook gives the world annual birthrate, mortality rate, and growth rate as 1.89%, 0.79%, and 1.096% respectively. The last 100 years have seen a rapid increase in population due to medical advances and massive increase in agricultural productivity.
Simora [160]3 years ago
3 0
Hello!

The human population is increasing so much because the death rate has gown down. The farther we go, the more technology we have available. Which in turn helps people live. So rapid birth rates and decreasing death rate is causing the rate to grow.
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(c) is the correct choice.

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3 years ago
Objects a and b each have a mass of 25 kilograms. object a has a velocity of 5.98 meters/second. object b is stationary. they un
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The total kinetic energy of the system after collision is 223.5J

In elastic collision kinetic energy and momentum are conserved.

According to the question

               mass of object a = 25kg

               mass of object b =  25 kg

        initial velocity of a u1 = 5.98 m/s

        initial velocity  of b u2 = 0

so from momentum conservation-

       mau1 + mbu2 = (m1+m2)v

       25kg × 5.98m/s + 25×0 = (25+25)v

              v = 2.99 m/s

Now the total kinetic energy after the collision will be:

          final kinetic energy = 1/2 (m1+m2) v²

                                           = 1/2 (25+25)× (2.99)²

                                           = 223.5 J

    Thus, total kinetic energy of the system after collision is 223.5J

Learn more about elastic collision here:

  brainly.com/question/1808045

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7 0
2 years ago
A 0.850 kg block is attached to a spring with spring constant 18 N/m . While the block is sitting at rest, a student hits it wit
Sveta_85 [38]

The block's speed at the point where x=0.25A is v = 31.95 cm/s.

<h3>What is Spring constant?</h3>

The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies. The stiffer the spring is and the harder it is to stretch, the bigger the spring constant.

question is incomplete, this is the remaining statement

What is the amplitude of the subsequent oscillations? And What is the block's speed at the point where x=0.25A?

x = Asin(wt)

v = Aw coswt

at t = 0

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v = Aw

A = v/w

A = 7.17 cm

part b )

E = 1/2mv^2 + 1/2kx^2 = 1/2kA^2

mv^2 + k(1/4A)^2 = 1/2kA^2

mv^2 + kA^2/16 = kA^2

mv^2 = kA^2 - kA^2/16

mv^2 = 15kA^2/16

v^2 = 15/16 * (k/m) * A^2

v^2 = 15/16 *w^2A^2

v = sqrt(15/16) * wA

v = 31.95 cm/s

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