I believe distillation is used to separate solvents of different kind as long as it is heated to its boiling temp
Answer:
Such molecule must have molecular formula of C15N3H15
Explanation:
Mass of carbon in such molecule
The atomic mass of carbon is 12.01 g/mol, so in 182.28 g of carbon there is 15.18 mols of carbon.
Mass of Nitrogen in such molecule
The atomic mass of nitrogen is 14.01 g/mol, so in 42.53g of nitrogen there is 3.04 mols of nitrogen.
Mass of Hydrogen in such molecule
The atomic mass of Hydrogen is 1.00 g/mol, so in 15.19 g of Hydrogen there is 15.19 mols of Hydrogen.
Such molecule must have molecular formula of C15N3H15
27*9=243 if one mole is equal to 27 grams times that by 9
By applying the Boyle's equation and substituting our given data the volume of the container was found to be 418.14 Litres
<h3>
Boyle's Law</h3>
Given Data
- number of moles of Ne = 5.1169 mol
We know that the relationship between pressure and temperature is given as
PV = nRT
R = 0.08206
Making the volume subject of formula we have
V= nRT/P
Substituting our given data to find the volume we have
V = 5.1169*0.08206*911/0.9148
V = 382.522353554/0.9148
V = 418.14 L
Learn more about Boyle's law here:
brainly.com/question/469270
2H2(g) + O2(g) → 2H2O(1) 0 260 g 0.2068 0.180 g 2008
When 45.0 g of CH4 reacts with excess O2, the actual yield of CO2 is 118 g. What is the percent yield? CHA(g) + 2O2(g) - CO2(g) + 2H2O(g) 73.6% 67.9% 95.2% 86.4%
For the reaction: 2503(g) + 790 kcal - 25(s) + 3O2(g), how many kcal are needed to form 1.5 moles O2(g)? 790 kcal 395 kcal 2370 kcal 411 kcal
When 3 moles of Ny are mixed with 5 moles of H2 the limiting reactant is N2(g) + 3H2(g) - 2NH3(g) H2 NH3 ОООО H20 O N₂
