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Debora [2.8K]
2 years ago
13

A 70.0 cm long string is vibrating in such a manner that it forms a standing wave with three antinodes. (The string is fixed at

both ends.)
Physics
1 answer:
Leya [2.2K]2 years ago
6 0

A 70.0 cm long string is vibrating in such a manner that it forms a standing wave with three antinodes. Third harmonic

<h3>What is antinodes?</h3>

The maximum wave amplitude is produced at the , which is the site of constructive interference of the incoming and reflected waves. The point at which destructive interference reduces the wave's amplitude to zero is known as a node. It should be simple to see that the antinodes have the highest vertical velocity, whilst the nodes have a strictly horizontal velocity. An antinode forms on a vertical border because the horizontal velocity component disappears there, whereas nodes are typically seen outside of solid bounds. The size and depth of a bay or estuary have a significant impact on the standing wave's characteristics. The center and two ends of a totally closed basin are referred to as nodes and antinodes, respectively.

To learn more bout antinodes  from the given link:

brainly.com/question/4248586

#SPJ4

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If four students separately measure the density of a rock, and they all have very low percent
lesya692 [45]

Answer:

Their measured results are closer to the exact or true value. Hence, their measured value is considered to be more accurate.

Explanation:

Considering the situation described above, the accuracy of a measured value depicts how closely a measured value is to the accurate value.

Hence, since the students' measured values have very low percent differences, it shows the similarity of computations or estimates to the actual values, which in turn offers a smaller measurement error.

Therefore, their measured results are closer to the exact or true value, which implies that their measured value is considered to be more accurate.

7 0
3 years ago
A block with mass M is placed on an inclined plane with slope angle q and is connected to a second hanging block with mass m by
tensa zangetsu [6.8K]

Answer:

The mass of the block m is:

m=M(sin(\theta)+\mu_{s}cos(\theta))

Explanation:

Let's analyze the block by parts

For the block M

T-W_{x}-f_{f}=0 (1)

Where:

  • T is the tension
  • W(x) is the component of the weight in the x-direction
  • F(f) is the friction force

T-Mgsin(\theta)-\mu_{s}N=0  

T-Mgsin(\theta)-\mu_{s}Mgcos(\theta)=0  

For the block m

T-W=0

T=mg (2)

Now, let's combines equation (1) and (2):

mg-Mgsin(\theta)-\mu_{s}Mgcos(\theta)=0  

Finally, let's solve it for block m.

mg-Mg(sin(\theta)+\mu_{s}cos(\theta))=0

m=M(sin(\theta)+\mu_{s}cos(\theta))

I hope it helps you!

7 0
3 years ago
A man is flying in a hot-air balloon in a straight line at a constant rate of 5 feet per second, while keeping it at a constant
icang [17]

Answer:

x = 220.85 ft

Explanation:

Let at any moment of time the friend's car is at some horizontal distance "x" from the position of balloon.

Now if the altitude of the balloon is fixed and it is at height "h"

so here we will have

tan \theta = \frac{h}{x}

now we know that

initially the angle of the friend's car is 35 degree

so the horizontal distance will be

x_1 = h cot35

similarly if the angle after passing the car position is 36 degree

then we have

x_2 = h cot36

now the speed of the balloon is constant

so we have

v = \frac{x_1 + x_2}{\Delta t}

5 ft/s = \frac{h cot35 + h cot36}{90 s}

5 ft/s = \frac{2.8h}{90}

h = 160.45 ft

so the final position of friend when the angle is 36 degree

x = \frac{h}{tan36}

x = \frac{160.45}{tan36}

x = 220.85 ft

4 0
3 years ago
1 - Don't put the coat on the snowman - it will melt him 2 - I don't think the coat will make any difference 3 - I think it will
Vinil7 [7]

Explanation:

I don't think the coat will make any difference

4 0
3 years ago
You cool a 130.0 g slug of red-hot iron (temperature 745 ∘C) by dropping it into an insulated cup of negligible mass containing
erik [133]

Answer:

A) 100°C

B) 211 g

Explanation:

Heat released by red hot iron to cool to 100°C = 130 x .45 x 645 [ specific heat of iron is .45 J /g/K]

= 37732.5 J

heat required by water to heat up to 100 °C = 85 x 4.2 x 80 = 28560 J

As this heat is less than the heat supplied by iron so equilibrium temperature will be 100 ° C. Let m g of water is vaporized in the process . Heat required for vaporization = m x 540x4.2  = 2268m J

Heat required to warm the water of 85 g to 100 °C = 85X4.2 X 80 = 28560 J

heat lost = heat gained

37732.5 = 28560 + 2268m

m = 4 g.

So  4 g of water will be vaporized and remaining 81 g of water and 130 g of iron that is total of 211 g will be in the cup . final temp of water will be 100 °C.

3 0
3 years ago
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