B.It will eventually slow down and fall to earth that’s what I think
Answer:
The current will be 3.23 A.
Explanation:
Given that,
Current I = 4.68 A
Voltage V = 220 volt
We need to calculate the resistance
Using ohm's law
![V = I R](https://tex.z-dn.net/?f=V%20%3D%20I%20R)
![R = \dfrac{V}{I}](https://tex.z-dn.net/?f=R%20%3D%20%5Cdfrac%7BV%7D%7BI%7D)
Where,
V = voltage
I = current
R = resistance
Put the value into the formula
![R = \dfrac{220}{4.68}](https://tex.z-dn.net/?f=R%20%3D%20%5Cdfrac%7B220%7D%7B4.68%7D)
![R = 47\ \Omega](https://tex.z-dn.net/?f=R%20%3D%2047%5C%20%5COmega)
We need to calculate the current
If the voltage drops by 31%
Voltage will be
![V'=V-V\times31%](https://tex.z-dn.net/?f=V%27%3DV-V%5Ctimes31%25)
![V'=220-220\times\dfrac{31}{100}](https://tex.z-dn.net/?f=V%27%3D220-220%5Ctimes%5Cdfrac%7B31%7D%7B100%7D)
![V'=151.8\ volt](https://tex.z-dn.net/?f=V%27%3D151.8%5C%20volt)
Now, the current will be
![I = \dfrac{151.8}{47}](https://tex.z-dn.net/?f=I%20%3D%20%5Cdfrac%7B151.8%7D%7B47%7D)
![I=3.23\ A](https://tex.z-dn.net/?f=I%3D3.23%5C%20A)
Hence, The current will be 3.23 A.
Given :
A wooden block is let go from a height of 5.80 m.
To Find :
The velocity of the block just before it hits the ground.
Solution :
We know, by equation of motion :
![v^2 - u^2 = 2as](https://tex.z-dn.net/?f=v%5E2%20-%20u%5E2%20%3D%202as)
Here, a = g = 9.8 m/s²( Acceleration due to gravity )
Putting all given values in above equation, we get :
![v^2 - u^2 = 2as\\\\v^2 -0 = 2\times 9.8 \times 5.8 \\\\v = \sqrt{2\times 9.8 \times 5.8 } \ m/s\\\\v = 10.66\ m/s](https://tex.z-dn.net/?f=v%5E2%20-%20u%5E2%20%3D%202as%5C%5C%5C%5Cv%5E2%20-0%20%3D%202%5Ctimes%209.8%20%5Ctimes%205.8%20%5C%5C%5C%5Cv%20%3D%20%5Csqrt%7B2%5Ctimes%209.8%20%5Ctimes%205.8%20%7D%20%5C%20m%2Fs%5C%5C%5C%5Cv%20%3D%2010.66%5C%20m%2Fs)
Hence, this is the required solution.
Open your image-editing software and load the photo you wish to work on.
Click "Filter," then "Sharpen" from the program's menu. You will likely see minor improvements to the image. ...
Click "Filter," "Sharpen," then "Smart Sharpen" for images where the normal sharpen tool is ineffective.