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ella [17]
3 years ago
12

Two individuals start the same training program at the same time, but one is able to grow muscle faster and larger than the othe

r. What is the least likely explanation for this?
A.
One individual was born with more muscle fibers.
B.
One individual has a more consistent training schedule.
C.
One individual is consuming a healthier diet.
D.
One individual has a more intense training schedule.
Physics
2 answers:
vitfil [10]3 years ago
7 0
I believe the answer is A
mestny [16]3 years ago
3 0

Answer:

the awnser is A girlies

Explanation:

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Physics help please! Offering 75 pts!
Nataliya [291]

Answer:

A

Explanation:

i got it from 2021 edge

5 0
2 years ago
Read 2 more answers
Suppose astronomers built a 150-meter telescope. how much greater would its light-collecting area be than that of the 10-meter k
Dennis_Churaev [7]
Almost all telescopes have a circular mirror. The area of a circle is proportional to r^2 where r is the radius of the circle, the constant of proportionality being 4\pi
S =4\pi r^2
Therefore the area of 150 meter telescope would be 
S_1/S_2=(r_1/r_2)^2 =(75/5)^2 =15^2=225
times bigger than the area of the smaller (10 meter) telescope.

6 0
2 years ago
What provides the force necessary to start a building or bridge oscillating?
Andrew [12]
Usually, the forces that start the oscillation of buildings are the wind and microearthquakes.
4 0
3 years ago
If a 400-mm diameter pipe with a pipe roughness coefficient of 100 flows full of pressurized water with a head loss of 0.4 ft pe
RoseWind [281]

Answer:

Q = 913.9 gpm

Explanation:

The Hazen Williams equation can be written as follows:

P = \frac{4.52\ Q^{1.85}}{C^{1.85}d^{4.87}}

where,

P = Friction Loss per foot of pipe = \frac{0.4}{1000\ ft} = 4 x 10⁻⁴

Q = Flow Rate in gallon/min (gpm) = ?

d = pipe diameter in inches = (400 mm)(0.0393701 in/1 mm) = 15.75 in

C = roughness coefficient = 100

Therefore,

4\ x \ 10^{-4} = \frac{4.52\ Q^{1.85}}{(100)^{1.85}(15.75)^{4.87}}\\\\Q^{1.85} = \frac{4\ x \ 10^{-4}}{1.33\ x\ 10^{-9}} \\\\Q = (300384.75)^\frac{1}{1.85}

<u>Q = 913.9 gpm</u>

5 0
3 years ago
Displacement vectors of 4 km north, 2 km south, 5 km north, and 5 km south combine to a total displacement of
valentinak56 [21]

south = -(north)

Displacement = (4 km north) + (2 km south) + (5 km north) + (5 km south)

Displacement = (4 km north) - (2 km north) + (5 km north) - (5 km north)

Displacement = (4 - 2 + 5 - 5) km north

<u>Displacement = 2 km north </u>

6 0
3 years ago
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