All categories

3 years ago

How are all paths that have a displacement of zero similar?

2 answers:

8 0

Displacement is identified as the net movement of a thing with detail to its initial location. One may journey out of his city and come back. Notwithstanding having enclosed many miles, he will have a displacement of 0. This is true for all trails that have zero displacement that they all go back to their initial position.

kotykmax [81]3 years ago

5 0

Any situation that has a path that stops at the same position that it started from has a dismantlement of zero.

You might be interested in

The equation of a transverse wave traveling along a very long string is y 6.0 sin(0.020px 4.0pt), where x and y are expressed in

zhannawk [14.2K]

Answer:

given

y=6.0sin(0.020px + 4.0pt)

the general wave equation moving in the positive directionis

y(x,t) = ymsin(kx -?t)

a) the amplitude is

ym = 6.0cm

we have the angular wave number as

k = 2p /?

? = 2p / 0.020p

=1.0*102cm

the frequency is

f = ?/2p

= 4p/2p

= 2.0 Hz

the wave speed is

v = f?

= (100cm)(2.0Hz)

= 2.0*102cm/s

since the trignometric function is (kx -?t) , sothe wave propagates in th -x direction

the maximum transverse speed is

umax =2pfym

= 2p(2.0Hz)(6.0cm)

= 75cm/s

we have

y(3.5cm ,0.26s) = 6.0cmsin[0.020p(3.5) +4.0p(0.26)]

= -2.0cm

6 0

3 years ago

A proton, which is the nucleus of a hydrogen atom, can be modeled as a sphere with a diameter of 2.4 fm and a mass of 1.67 10-27

Step2247 [10]

For the answer to the question above asking to determine the density of the proton.
Density is mass over volume.

The volume of a sphere is 4πr³/3. r is half the diameter.

So the density would be 2.3×10¹⁷ kg/m³.
I hope my answer helped you. Feel free to ask more questions. Have a nice day!

8 0

3 years ago

Read 2 more answers

Calculate the acceleration of an airplane that starts at rest and reaches a speed 45m/s in 9 seconds

sasho [114]

I believe the acceleration would be 5m/s

All you would need to do is divide the final speed by the time it took to get there. I am only about 80 sure this answer is correct, so take my advise only if you feel comfortable.

3 0

3 years ago

Read 2 more answers

I need homework help

KIM [24]

1) the weight of an object at Earth's surface is given by $F=mg$ , where m is the mass of the object and $g=9.81 m/s^2$ is the gravitational acceleration at Earth's surface. The book in this problem has a mass of m=2.2 kg, therefore its weight is
$F=mg=(2.2 kg)(9.81 m/s^2)=21.6 N$

2) On Mars, the value of the gravitational acceleration is different: $g=3.7 m/s^2$ . The formula to calculate the weight of the object on Mars is still the same, but we have to use this value of g instead of the one on Earth: $F=mg=(2.2 kg)(3.7 m/s^2)=8.1 N$

3) The weight of the textbook on Venus is F=19.6 N. We already know its mass (m=2.2 kg), therefore by re-arranging the usual equation F=mg, we can find the value of the gravitational acceleration g on Venus:
$g= \frac{F}{m}= \frac{ 19.6 N}{2.2 kg}=8.9 m/s^2$

4) The mass of the pair of running shoes is m=0.5 kg. Their weight is F=11.55 N, therefore we can find the value of the gravitational acceleration g on Jupiter by re-arranging the usual equation F=mg:
$g= \frac{F}{m} = \frac{11.55 N}{0.5 kg} =23.1 m/s^2$

5) The weight of the pair of shoes of m=0.5 kg on Pluto is F=0.3 N. As in the previous step, we can calculate the strength of the gravity g on Pluto as
$g= \frac{F}{m} = \frac{0.3 N}{0.5 kg} =0.6 m/s^2$

6) On Earth, the gravity acceleration is $g=9.81 m/s^2$ . The mass of the pair of shoes is m=0.5 kg, therefore their weight on Earth is
 $F=mg=(0.5 kg)(9.81 m/s^2)=4.9 N$

5 0

3 years ago

Which requires more work, carrying a 420 N knapsack up a 200 m hill or carrying a 210 knapsack up a 400 m hill? Why?

Katen [24]

Answer:

Explanation:

because the weight/work increases bcz of the time period

4 0

3 years ago