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3 years ago

Calculate the magnitude of the force exerted by each wire on a 1.20-m length of the other.

Physics

1 answer:

Zielflug [23.3K]3 years ago

4 0

Incomplete question.The complete question is attached below as screenshot along with figure

Answer:

$F=6.00*10^{-6}N$

Force is repulsive

Explanation:

Given data

Current I₁=5.00A

Current I₂=2.00A

Length L=1.20 m

Radius r=0.400m

To find

Force F

Solution

As the force is repulsive because currents are in opposite direction

From repulsive force we know that:

$F=\frac{u_{o}I_{1}I_{2}L}{2\pi r}$

Substitute the given values

$F=\frac{u_{o}(5.00A)(2.00A)(1.20m)}{2\pi (0.400m)}\\ F=6.00*10^{-6}N$

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The mass of a string is 5.9 × 10-3 kg, and it is stretched so that the tension in it is 200 n. a transverse wave traveling on th

bagirrra123 [75]

The velocity of the wave on the string is given by

$v=\sqrt{\frac{T}{\frac{m}{L}}} \\ v=\sqrt{\frac{TL}{m}}$

Solving the above equation,

$v^2=\frac{TL}{m} \\ L=\frac{v^2m}{T}$

The frequency of the wave $f=300$ and wave length is $0.76$

The velocity is $v=(300)(0.76)=228$

Substituting numerical values,

$L=\frac{228^2(0.0059)}{200}\\ T=1.534$

The length of the string is $1.534 m$

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3 years ago

What are beats

N76 [4]

Beats can be defined as the periodic fluctuations in the frequency of sound waves. That is option D

<h3>What are sound waves?</h3>

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brainly.com/question/15663649

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4 0

2 years ago

Object A and Object B have the same volume of 10 cm³. Object A has a mass of 20 grams. Object B has a mass of 50 grams. Which ob

aniked [119]

Answer:

Object B has greater density

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the object that has greater mass has the greater density because the volume of the those two objects are same

3 0

3 years ago

A. Compute the torque developed by an industrial motor whose ouputis 150kW at an angular speed of 4000 rev/min.

Gnom [1K]

Answer:

A. τ = 358 N.m

B. m = 73kg

C. V = 209.5 m/s

Explanation:

Let's first convert angular speed to rad/s:

ω = 4000 rev/min * 2π / 60 = 419 rad/s

Since Power is P = τ * ω,

τ = P / ω = 358 N.m

For part B: On the hanging weight:

T - m*g = 0

T = m*g

On the drum:

τ = T*R Replacing the expression for Tension of the rope:

τ = m*g*R

Solving for m:

m = 73 kg

For part C:

V = ω * R = 209.5 m/s

5 0

2 years ago

Can anyone wanna help me

FrozenT [24]

I'd say the answer's D.

7 0

3 years ago