Question

Calculate the magnitude of the force exerted by each wire on a 1.20-m length of the other.

Answer 1

Incomplete question.The complete question is attached below as screenshot along with figure

Answer:

$F=6.00*10^{-6}N$

Force is repulsive

Explanation:

Given data

Current I₁=5.00A

Current I₂=2.00A

Length L=1.20 m

Radius r=0.400m

To find

Force F

Solution

As the force is repulsive because currents are in opposite direction

From repulsive force we know that:

$F=\frac{u_{o}I_{1}I_{2}L}{2\pi r}$

Substitute the given values

$F=\frac{u_{o}(5.00A)(2.00A)(1.20m)}{2\pi (0.400m)}\\ F=6.00*10^{-6}N$