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rewona [7]
3 years ago
7

Calculate the magnitude of the force exerted by each wire on a 1.20-m length of the other.

Physics
1 answer:
Zielflug [23.3K]3 years ago
4 0

Incomplete question.The complete question is attached below as screenshot along with figure

Answer:

F=6.00*10^{-6}N

Force is repulsive

Explanation:

Given data

Current I₁=5.00A

Current I₂=2.00A

Length L=1.20 m

Radius r=0.400m

To find

Force F

Solution

As the force is repulsive because currents are in opposite direction

From repulsive force we know that:

F=\frac{u_{o}I_{1}I_{2}L}{2\pi r}

Substitute the given values

F=\frac{u_{o}(5.00A)(2.00A)(1.20m)}{2\pi (0.400m)}\\ F=6.00*10^{-6}N

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⊱┈────────────────────────┈⊰

\large \bold {ANSWER}

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\large \bold {EXPLANATION}

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