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rewona [7]
3 years ago
7

Calculate the magnitude of the force exerted by each wire on a 1.20-m length of the other.

Physics
1 answer:
Zielflug [23.3K]3 years ago
4 0

Incomplete question.The complete question is attached below as screenshot along with figure

Answer:

F=6.00*10^{-6}N

Force is repulsive

Explanation:

Given data

Current I₁=5.00A

Current I₂=2.00A

Length L=1.20 m

Radius r=0.400m

To find

Force F

Solution

As the force is repulsive because currents are in opposite direction

From repulsive force we know that:

F=\frac{u_{o}I_{1}I_{2}L}{2\pi r}

Substitute the given values

F=\frac{u_{o}(5.00A)(2.00A)(1.20m)}{2\pi (0.400m)}\\ F=6.00*10^{-6}N

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What is the unit of measurement of velocity
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What is an asteroid that is pulled off course by a planet’s gravity and orbits around that planet called?
tresset_1 [31]

The definition of the celestial bodies allows us to find that the correct answer for a body that is captured and is in planetary orbit is:

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A meteorite is a fragment of meteoroid, which has been divided in space or the atmosphere during the entrance to the planet, in general they are smaller

A meteor is the atmospheric phenomenon that occurs when the pattern meteorite or meteoroid enters, that is, it does not correspond to a celestial body.

An asteroid satellite or Moon is a celestial object that revolves captures and around another asteroid, this concept can be extended to an asteroid revolving captures and around a planet

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Let's examine the different answers

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True. A body captured by a planet is generally called the Moon.

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False. A meteoroid is a body that enters the atmosphere of the plant and reaches its surface.

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False. It is a fragment of meteoroid that manages to reach the surface of the planet.

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False.   Atmospheric phenomenon visible when passing a meteoroid or meteorite.

In conclusion, using the definition of celestial bodies we can find that the correct answer for a body that is captured and is in planetary orbit is:

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