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ozzi
3 years ago
13

A dragster runs the quarter mile in 8.96 s. What is the car's velocity (in ft/s) at the finish line?

Physics
1 answer:
lara [203]3 years ago
7 0
The first thing you should know to answer this question is the following conversion:
 1mi = 5280feet
 We have then that the speed is:
 v = ((1/4) * (5280)) / (8.96)
 v = 147.32 feet / s
 Answer:
 the car's velocity (in ft / s) at the finish line is 147.32 feet / s
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Speed = distance / time.

Speed of him leaving the nest:
S = 100 / 20sec

5 m/s.

Catching the snake:
S2 = 50 / 5sec

10 m/s.

Average of 5& 10 = 7.5

7.5 m/s has to be the answer.
3 0
3 years ago
A solenoid with an air core has a magnetic field pointing along its axis in the positive x direction. This solenoid is then fill
trapecia [35]

Answer:

we can say that with a smaller magnitude , the field will point is in same direction

Explanation:

we have given that

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6 0
3 years ago
A refrigerator having a power rating of 350W operates for 12 hours a day. calculate the cost of electrical energy to operate it
rodikova [14]

Answer:

See the answers below.

Explanation:

The cost of energy can be calculated by multiplying each given value, a dimensional analysis must be taken into account in order to calculate the total value of the cost in Rs.

Cost=0.350[kW]*12[\frac{hr}{1day}]*30[days]*4.5[\frac{Rs}{kW*hr} ]=567[Rs]

The fuse can be calculated by knowing the amperage.

P=V*I

where:

P = power = 350 [W]

V = voltage = 240 [V]

I = amperage [amp]

Now clearing I from the equation above:

I=P/V\\I=350/240\\I=1.458[amp]

The fuse should be larger than the current of the circuit, i.e. about 2 [amp]

3 0
2 years ago
A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. What is
loris [4]

Answer:

The acceleration of the crate is 1.82\ m/s^2.

Explanation:

Given that,

Force, F = 750 N

Mass of the crate, m = 250 kg

The coefficient of friction is 0.12.

We need to find the acceleration of the crate. The net force acting on the crate is given by :

F=ma\\\\F-f=ma

f is frictional force, f=\mu N=\mu mg

F-\mu mg=ma\\\\a=\dfrac{F-\mu mg}{m}\\\\a=\dfrac{750-0.12\times 250\times 9.8}{250}\\\\a=1.82\ m/s^2

So, the acceleration of the crate is 1.82\ m/s^2. Hence, this is the required solution.

4 0
3 years ago
Please can someone help?
vodomira [7]
5207 because I said so
5 0
2 years ago
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