Answer:
Force= work done/time taken
so, 45j/3s
force= 15 N
Explanation:
Answer:
the electric charge in the Earth is -5.91 × 10⁵ C
Explanation:
Given the data in the question;
Electric field E = 131 N/C
we know that; radius of the earth r = 6,371 km = 6371000 m
and Coulomb's constant k = 8.99 × 10⁹ Nm²/c²
Now, using the following formula to calculate the charge;
E = k × Q/r²
we make Q the subject of the formula
Q = Er² / k
so we substitute
Q = [ 131 N/C × ( 6371000 m )² ] / 8.99 × 10⁹ Nm²/c²
Q = [ 5.317242971 × 10¹⁵ ] / [ 8.99 × 10⁹ ]
Q = 5.91 × 10⁵ C
Since the electric field pointing downward
Q = -5.91 × 10⁵ C
Therefore, the electric charge in the Earth is -5.91 × 10⁵ C
A. Average speed is weighted mean (1 × 2 + 2 × 3 + 3 × 5 + 4 × 7 + 3 × 9 + 2 × 12.5)/15 = (2 + 6 + 15 + 28 + 27 + 25)/15 = 103/15 = 6.867 b. RMS is square root of 1/15 times sum of squares of speeds Sum of squares is 4 + 9 + 9 + 25 + 25 + 25 + 49 + 49 + 49 + 49 + 81 + 81 + 81 +156.25 + 156.25 = 848.5
c. RMS speed = √(848.5/15) = 7.521
Most likely the speed is the peak in the speed distribution, which is 7.
Answer:

Explanation:
We are given that
Current=I=1.75 A
Resistance =R=55.4 ohm
Time=t=9.5 min=
1 min=60 s
We have to find the heat generated by the resistor.
We know that
Heat=E=
Using the formula
Heat,
Hence, the heat generated by the resistor =
Answer:

Explanation:
<u>Given:</u>
= uniform electric field in the space = 
- Q = Charge placed in the region =

<u>Assume:</u>
= Electric force on the charge due to electric field
We know that the electric field is the electric force applied on a unit positive charge i.e.,

This means the electric force applied on this additional charge placed in the field is given by:

From the above expression of force, we have the following y-component of force on this additional charge.

Hence, the y-component of the electric force on the this charge is
.