Answer:
None of the options are correct. The correct answer is 30020J
Explanation:
Data obtained from the question include:
Mass (M) = 2000g
Initial temperature (T1) = 10°C
Final temperature (T2) = 29°C
Change in temperature (ΔT) = T2 - T1 = 29°C - 10°C = 19°C
Heat (Q) =?
Specific heat capacity (C) of granite = 0.79J/g°C
Applying the equation Q = MCΔT, the heat absorbed by the granite rock can be obtained as follow:
Q = MCΔT
Q = 2000 x 0.79 x 19
Q = 30020J
Answer:
a) ppm
b) ppm
c) ppb
d) ppt
e) ppb
Explanation:
a) You know that 1000 g are 1 kg, and 1000 kg are 1 ton, so (1000)*(1000) g are 1 ton, so 1,000,000 grams are one ton.
b) 1000 mg are 1 g, and 1000 g are 1 liter, so 1,000,000 grams are one liter.
c) You know that 1000 ug are 1 mg, so with the b), we just need to multiply the answer by 1000, so 1,000,000,000 ug are 1 liter.
d) The same as c, 1000 ng are 1 mg. So we are talkinf of ppt.
e) 1000 mg are 1 g. And 1000 g are 1 kg, then 1000 kg are one ton. So 1,000,000,000 mg are one ton.
Answer:
Mass = 0.697 g
Explanation:
Given data:
Volume of hydrogen = 1.36 L
Mass of ammonia produced = ?
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Solution:
Chemical equation:
3H₂ + N₂ → 2NH₃
First of all we will calculate the number of moles of hydrogen:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
1atm ×1.36 L = n × 0.0821 atm.L/mol.K × 273.15 K
1.36 atm.L = n × 22.43 atm.L/mol
n = 1.36 atm.L / 22.43 atm.L/mol
n = 0.061 mol
Now we will compare the moles of hydrogen and ammonia:
H₂ : NH₃
3 : 2
0.061 : 2/3×0.061 = 0.041
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 0.041 mol × 17 g/mol
Mass = 0.697 g
Answer:
14 solubility in 200 gram of water at 20 c
Explanation:
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