Answer:
Explanation:
Given that,
Bathysphere radius
r = 1.5m
Mass of bathysphere
M = 1.2 × 10⁴ kg
Constant speed of descending.
v = 1.2m/s
Resistive force
Fr = 1100N upward direction
Density of water
ρ = 1.03 × 10³kg/m³
The volume of the bathysphere can be calculated using
V = 4πr³ / 3
V = 4π × 1.5³ / 3
V = 14.14 m³
The Bouyant force can be calculated using
Fb = ρgV
Fb = 1.03 × 10³ × 9.81 × 14.14
Fb = 142,846.18 N
Buoyant force is acting upward
Weight of the bathysphere
W = mg
W = 1.2 × 10⁴ × 9.81
W = 117,720 N
Weight is acting downward
The net positive buoyant using resolving
Fb+ = Fb — W
Fb+ = 142,846.18 — 117,720
Fb+ = 25,126.18 N
The force acting downward is the weight of the submarine and it is equal to the positive buoyant force and the resistive force
W = Fb+ + Fr
W = 25,126.18 + 1100
W = 26,226.18
mg = 26,226.18
m = 26,226.18 / 9.81
m = 2673.4kg
Mass of submarine is 2673.4kg
In general, the Earth releases energy back to the atmosphere through reflection, evaporation, and radiation. The Earth gets energy from the sunlight, part of which it absorbs, while part it reflects backwards, thus giving energy to the atmosphere. Also, the heating up of the Earth by the absorbed sunlight, radiates back in the lower layers of the atmosphere, again giving back energy to it. The water vapor is another way in which the Earth gives back energy tot he atmosphere as through the evaporation, the water vapor gets into the lower parts of the atmosphere and gives energy to it.
Answer:
The final velocity of the plane is 100 m/s.
Explanation:
To solve this problem, we will use one the kinematics equations. First, let's write out what information we have given and what we are trying to find.
x = 5.0 * 10^2 m
a = 5.0 m/s^2
v1 = 0 m/s (starts from rest)
v2 = ? (we are trying to find the final velocity)
Using the variables listed above, we can select the following equation to use:
v2^2 = v1^2 + 2ax
Now, we should plug in our known values and isolate the unknown variable.
v2^2 = 0 + 2(10)(500)
To solve for the velocity, we should take the square root of both sides of the equation to get rid of the square on the left side of the equation.
v = sqrt(10,000)
Now, we must simplify the right side of the equation to solve for v (the unknown variable).
v = 100 m/s
Therefore, your answer is 100 m/s.
Hope this helps!
It’s B I’m not sure it the right one
Answer:
500m/s
Explanation:
From the question we are given the following;
mass per unit length = 4.80 x10^-3 kg/m
Tension T = 1200N
Speed of the wave is expressed as;
v = √T/m
v = √1200/0.0048
v = √250,000
v = 500m/s
Hence the speed at which the wave travels on this string is 500m/s
