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melisa1 [442]
3 years ago
13

Materials A, B, and C are solids that are at their melting temperatures. Material A requires 200 J to melt 4 kg, material B requ

ires 300 J to melt 5 kg, and material C requires 300 J to melt 6 kg. Rank the materials according to their heats of fusion. If multiple materials rank equally, use the same rank for each, then exclude the intermediate ranking (i.e. if objects A, B, and C must be ranked, and A and B must both be ranked first, the ranking would be A:Greatest, B:Greatest, C:Third greatest). If all materials rank equally, rank each as 'Greatest'.
Physics
1 answer:
Bingel [31]3 years ago
8 0

Answer:

B: Greatest, A: Second greatest, C: Second geratest.

Explanation:

We can calculate the heat of fusion of a material (ΔHfus), which is the heat required to melt 1 kg of material, using the following expression.

ΔHfus = Q/m

where,

  • Q: heat provided
  • m: mass

Material A

ΔHfus = 200 J/4 kg = 50 J/kg

Material B

ΔHfus = 300 J/5 kg = 60 J/kg

Material C

ΔHfus = 300 J/6 kg = 50 J/kg

Then, considering the heats of fusion,

B: Greatest, A: Second greatest, C: Second greatest.

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Torque is the force that tends to rotate the body to which it was applied.

To calculate the net torque, we use the formula below

Formula:

  • τ = mgd-m'gd'........... Equation 1

Where:

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From the question,

Given:

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Substitute these values into equation 1

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Hence, The net torque on the seesaw is 294 Nm.

Learn more about torque here: brainly.com/question/14839816

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