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Feliz [49]
3 years ago
9

0.1 (0.5 + 6) = 2 I thank you a million who ever helps me

Mathematics
1 answer:
Damm [24]3 years ago
6 0

Answer:

m = 28

Step-by-step explanation:

Simplifying

0.1(0.5m + 6) = 2

Reorder the terms:

0.1(6 + 0.5m) = 2

(6 * 0.1 + 0.5m * 0.1) = 2

(0.6 + 0.05m) = 2

Solving

0.6 + 0.05m = 2

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-0.6' to each side of the equation.

0.6 + -0.6 + 0.05m = 2 + -0.6

Combine like terms: 0.6 + -0.6 = 0.0

0.0 + 0.05m = 2 + -0.6

0.05m = 2 + -0.6

Combine like terms: 2 + -0.6 = 1.4

0.05m = 1.4

Divide each side by '0.05'.

m = 28

Simplifying

m = 28

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3 years ago
What is 26% of 160?<br> A. 4.16<br> B. 6.15<br> C. 41.6<br> D. 61.5
Vinvika [58]

Answer:

41.6

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
I’ll give brainliest please help it's due in 30 min
nirvana33 [79]
Answer: √8
Explanation: x=(5/√8) x (√8 √8)
6 0
3 years ago
The high temperature Monday was 4 degrees. The low temperature was -7 degrees. What is the difference between the high and low t
OleMash [197]

Answer:

Hey there!

We are trying to find the difference between 4 and -7

We can write -7+x=4, where x is the difference we are trying to find.

Solving for x, we get that the difference is 11.

Let me know if this helps :)

7 0
3 years ago
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