Draw CO2, C in the middle and O on each side. O has 6 e- and C has 4, so 6+6+4= 14 e-.
I think it’s the constants
<span>One degree Celsius indicates the same temperature change as one </span>
Answer:
Mass = 9.8 g
Explanation:
Given data:
Molarity of solution = 0.2 M
Volume of solution = 500 mL
Number of grams of phosphoric acid = ?
Solution:
First of all we will convert the volume milliliter to litter.
500 mL × 1 L/1000 mL
0.5 L
Molarity = moles of solute / volume in litter
0.2 M = number of moles / volume in litter
Number of moles = 0.2 mol/L × 0.5 L
Number of moles = 0.1 mol
Number of grams:
Number of moles = mass/molar mass
Mass = number of moles × molar mass
Mass = 0.1 mol × 98 g/mol
Mass = 9.8 g
When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105j/mol, then the equilibrium constant at 2400 k is 2.21×10−3. The answer to the statement is 2.21×10−3.
