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Alika [10]
3 years ago
8

PLEASE ANSWER ASAP!!!!! Object A has a mass of 12 g and a volume of 8 cm3. Object B has a mass of 20 g and a volume of 8 cm3. Wh

ich object has a greater density and by how much? A: Object A, by 1 gram per cubic centimeter B: Object A, by 8 grams per cubic centimeter C: Object B, by 1 gram per cubic centimeter D. Object B, by 8 grams per cubic centimeter
Chemistry
2 answers:
ludmilkaskok [199]3 years ago
6 0
Density = mass divided by volume
Amiraneli [1.4K]3 years ago
3 0
The answer is the first one <span />
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Level 1: 2Sr + 02 &gt; 2Sro
tekilochka [14]

Answer:

Sr would be the limiting reactant

5 moles

Explanation:

Since the equation is a balanced equation, the coefficient shows how each substance relates to the other in terms of the number of moles.

Reactants would be those on the left hand side of the arrow, while the products would be found on te right and side of the arrow. In this question, the reactants would be Sr and O₂.

Limiting reactant is the reactant that is insufficient; meaning to say that there is not enough of that substance and thus the reaction cannot continue. The other reactant(s) that is not limiting is called the excess reactants.

From the balanced equation, 2 moles of Sr is needed to react with 1 mole of O₂. Thus, if we have 5 moles of each reactant, Sr would be the limiting reactant since for every 1 mole of O₂, there has to be 2 moles of Sr in order for the reaction to proceed. Thus, if we have 5 moles of O₂, we would need 10 moles of Sr.

When we work out the amount of products formed, we look at the number of moles of the limiting reactant. This is because the limiting reactant determines how much is being reacted, while the excess number of moles of the excess reactant will remain unreacted.

For every 2 moles of Sr reacted, 2 moles of SrO would be produced. This means that the mole ratio of Sr to SrO is 1:1. Thus, since 5 moles of Sr has been reacted, 5 moles of the product (SrO) would be produced.

8 0
3 years ago
Zn-64 = 48.63%
sladkih [1.3K]

Answer:

A = 65.46 u

Explanation:

Given that,

The composition of zinc is as follows :

Zn-64 = 48.63%

Zn-66 = 27.90%

Zn-67 = 4.10%

Zn-68 = 18.75%

Zn-70 = .62%

We need to find the  average atomic mass of the given element. It can be solved as follows :

A=\dfrac{48.63\times 64+27.90\times 66+4.1\times 67+18.75\times 68+0.62\times 70}{100}\\A=65.46\ u

So, the average atomic mass of zinc is 65.46 u.

6 0
2 years ago
24 grams of magnesium metal reacts with 16 grams of oxygen gas to form magnesium oxide according to the law of conservation of m
galina1969 [7]
X,,s,smells,s,wow,masks,as,mw
8 0
3 years ago
The decomposition of 57.0 g of Fe2O3 results in Consider the following reaction. 2Fe2O3 ---&gt; 4Fe + 3O2 deltaH degree rxn = +
lozanna [386]

Answer:

The correct answer is option E.

Explanation:

2Fe_2O_3\rightarrow 4Fe + 3O_2 \Delta H^o_{rxn} = 824.2 kJ

Mass of ferric oxide decomposed = 57.0 g

Moles of ferric oxide decomposed = \frac{57.0 g}{160 g/mol}=0.35625 mol

According to reaction, 2 moles ferric oxide on combustion gives 824.2 kJ of heat.

Then heat given by on decomposition of 0.35625 mol of ferric oxide will be:

\frac{824.2 kJ}{2}\times 0.35625 =146.81 kJ\approx 147 kJ

So, on decomposition of 57.0 grams of ferric oxide 147 kilo Joules of heat was released.

3 0
3 years ago
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