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Alika [10]
2 years ago
8

PLEASE ANSWER ASAP!!!!! Object A has a mass of 12 g and a volume of 8 cm3. Object B has a mass of 20 g and a volume of 8 cm3. Wh

ich object has a greater density and by how much? A: Object A, by 1 gram per cubic centimeter B: Object A, by 8 grams per cubic centimeter C: Object B, by 1 gram per cubic centimeter D. Object B, by 8 grams per cubic centimeter
Chemistry
2 answers:
ludmilkaskok [199]2 years ago
6 0
Density = mass divided by volume
Amiraneli [1.4K]2 years ago
3 0
The answer is the first one <span />
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Write Huckel's rule below and determine how many electrons are required to make an aromatic ring with n = 0, 1, and 2.
lisov135 [29]

<u>Answer:</u> The number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

<u>Explanation:</u>

Huckel's rule is used to determine the aromaticity in a compound. The number of delocalized \pi- electrons are calculated by using the equation:

\text{Number of delocalized }\pi-\text{ electrons}=4n+2

where,

n = 0 or any whole number

  • Calculating the value of electrons for n = 0

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(0)+2=2

  • Calculating the value of electrons for n = 1

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(1)+2=6

  • Calculating the value of electrons for n = 2

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(2)+2=10

Hence, the number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

4 0
3 years ago
Which of these is not true about weight
skelet666 [1.2K]

Answer:

its b beacuse different things have different mass

4 0
2 years ago
If an element only partially conducts electricity, it would be part of the _______ category. *
dmitriy555 [2]
It would be in the transition metals
5 0
2 years ago
Why was mass lost from the crucible during the reaction?
Alexxandr [17]
If the crucible wasn't covered with a lid the reactants may have produced a gas that was released into the surroundings, or mass may have been lost in the form of water vapour.
6 0
2 years ago
13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What
rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

<em>of MgCO3.3H2O in the mixture?</em>

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

<em>Mass water:</em>

3.883g - 2.927g = 0.956g water

<em>Moles water -18.01g/mol-</em>

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

<em>Moles MgCO3.3H2O:</em>

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

<em>Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-</em>

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

<em>Mass percent:</em>

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

<h3>63.05% of MgCO3.3H2O by mass</h3>
6 0
2 years ago
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