Explanation:
a particle smaller than an atom (e.g., a neutron) or a cluster of such particles (e.g., an alpha particle).
Answer: 34.4 g
Explanation:


As
is in excess,
is the limiting reagent and thus it will limit the formation of products.

According to stoichiometry:
2 moles of hydrogen produce = 1 mole of 
2.5 moles of hydrogen produce =
of 
Mass of 
But as % yield is 86%, mass of
produded is 
Thus 34.4 g of
is produced.
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Moles of Ammonia produced : 4 moles
<h3>Further explanation</h3>
Given
6 mol of H₂
Required
moles of Ammonia
Solution
Reaction
N₂ + 3H₂ → 2NH₃
In chemical equations, the reaction coefficient shows the mole ratio of the reacting compound (reactants and products)
From the equation, mol ratio of H₂ : NH₃ = 3 : 2, so mol NH₃ :
= 2/3 x moles H₂
= 2/3 x 6
= 4 moles