Well, when an atom attains a stable valence electron, it means that the outer electrons are complete and so cannot attain any more electrons. For the first shell, it is complete when it has 2 electrons, the second shell is complete when it has 8 electrons, all the other shells also have a particular number when complete. Anyway, i believe the answer is HYDROGEN because when HYDROGEN combines with another atom of HYDROGEN, the outer shell is completed. This is because HYDROGEN has only 1 electron. If the two HYDROGENS, which both have 1 electron combine, they make the electrons 2, which is complete for the first shell, HYDROGEN ends in the first shell. Since the electrons become 2, the shell is at stable valence. In all the other options, this happens;
NEON- It has 10 electrons, 2 in the first shell and 8 in the second. So the the shells are already complete, so it can't bond with any thing, which is completely against the question.
RADON- Radon has 86 electrons.
HELIUM- Helium has 2 electrons, so the shell is already full, and cannot bond, so it goes against the question. The question says BY BONDING.
So the answer is definitely 4) HYDROGEN
Hope i helped. Have a nice day, by the way, i'm very sure it's hydrogen.
Ba(ClO3)2 --> BaCl2 + 3 O2
The fact that there are some ionic compounds doesn't matter. Just use the formulas.
barium chlorate = Ba(ClO3)2
barium chloride = BaCl2
Oxygen = O2
Now create the unbalanced equation
Ba(ClO3)2 --> BaCl2 + O2
And balance in the usual fashion. Count the atoms of each element on both sides
Ba = 1, 1
Cl = 2, 2
O = 6, 2
And oxygen is out of balance. But can be easily handled with a 3 coefficient on the right hand side. So:
Ba(ClO3)2 --> BaCl2 + 3 O2
And we have a balanced equation.
Explanation:
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