Answer is 2m/s sq because V-u /t us acceleration 40-10/15=2
# of atoms per mol = Avogadro’s # (6.022 x 10^23)
Number of mols = mass of substance / molar mass
73 g / 40.08 g = 1.8 mols of Ca in 73 grams
1.8 mols x avagadro’s # = 1.1 x 10^24 atoms in 73 grams of Ca
0 N stopping at stop sign.
Answer:
1.
Since both components of these solutions have the same molar mass, mole fractions would be the same as mass fractions.
0.110 atm = (2/3)(Pi) + (1/3)(Pn) [1]
0.089 atm = (1/3)(Pi) + (2/3)(Pn) [2]
2*[1] - [2]:
(2)(0.110) - 0.089 atm = Pi
Pi = 0.131 atm
2*[2] - [1]:
(2)(0.089) - 0.110 atm = Pn
Pn = 0.068 atm
2.
The hydroxyl (-OH) group on the end of a longer 1-propanol molecule makes it more polar than IPA. It follows that the intermolecular forces between 1-propanol are stronger than those of IPA and thus the vapor pressure of 1-propanol should be lower than IPA.
Explanation: