when hydrogen atom absorbs a photon, and an electron moves level 1 to level 2, what happens to the energy of the atom?

Chemistry

1 answer:

pychu [463]2 years ago

7 0

Answer:

When an electron is hit by a photon of light, it absorbs the quanta of energy the photon was carrying and moves to a higher energy state. One way of thinking about this higher energy state is to imagine that the electron is now moving faster, (it has just been "hit" by a rapidly moving photon).

Explanation: pls mark brainliest :))

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For the 1st order reactions,rate constant (k) is mathematically expressed as

k = $\frac{2.303}{t}log \frac{Co}{Ct}$
where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'

Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s

Therefore, we have
</span>2.20 × 10^-5 = $\frac{2.303}{7200}log \frac{100}{Ct}$
∴ $log\frac{100}{Ct}$ = 0.06877
∴, $\frac{100}{Ct}$ = 1.1716
∴, Ct = 85.35%

Thus, <span>85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>

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