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AfilCa [17]
3 years ago
15

Nitric acid is often manufactured from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming of natural

gas, in a two-step process. In the first step, nitrogen and hydrogen react to form ammonia: N2(g) + 3H2(g) ---> 2NH3(g) In the second step, ammonia and oxygen react to form nitric acid and water: NH3(g) + 2O2(g) ---> HNO3(g) + H2O(g) Write the net chemical equation for the production of nitric acid from nitrogen, hydrogen and oxygen. Be sure your equation is balanced.
Chemistry
1 answer:
hoa [83]3 years ago
4 0

<u>Answer:</u> The net chemical equation is given below.

<u>Explanation:</u>

To determine the net chemical equation, we will look into the intermediate steps:

<u>Step 1:</u> Formation of ammonia from hydrogen and nitrogen gas.

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)        ......(1)

<u>Step 2:</u> Formation of nitric acid from ammonia and oxygen gas.

NH_3(g)+2O_2(g)\rightarrow HNO_3(g)+H_2O(g)      .....(2)

The net chemical equation for the formation of nitric acid from hydrogen gas, nitrogen gas and oxygen gas follows by adding both the equations, we get:

N_2(g)+2O_2(g)+3H_2(g)\rightarrow HNO_3(g)+H_2O(g)+NH_3(g)

By Stoichiometry of the reaction:

1 mole of hydrogen gas reacts with 2 moles of oxygen gas and 3 moles of hydrogen gas to produce 1 mole of nitric acid, 1 mole of water and 1 mole of ammonia.

Hence, the net chemical equation is given below.

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A 5.00g of X, the product of organic synthesis is obtained in a 1.0 dm3 aqueous solution. Calculate the mass of X that can be ex
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mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

Explanation:

The partition coefficient of X between ethoxy ethane (ether) and water, K is given by the formula

K = concentration of X in ether/concentration of X in water

Partition coefficient, K(X) between ethoxy ethane and water = 40

Concentration of X in ether = mass(g)/volume(dm³)

Mass of X in ether = m g

Volume of ether = 50/1000 dm³ = 0.05 dm³

Concentration of X in ether = (m/0.05) g/dm³

Concentration of X in water = mass(g)/volume(dm³)

Mass of X in water left after extraction with ether = (5 - m) g

Volume of water = 1 dm³

Concentration of X in water = (5 - m/1) g/dm³

Using K = concentration of X in ether/concentration of X in water;

40 = (m/0.05)/(5 - m)

(m/0.05) = 40 × (5 - m)

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