Answer:
I think option A is right answer
Answer:
2NaCN + CaCO3 --> Na2CO3 + Ca(CN)2
Explanation:
Knowing the names gets us: NaCN + CaCO3 --> Na2CO3 + Ca(CN)2
Balance: there are two sodiums and cyanides on the product side so add a 2 to the reactant side.
Answer:
+2.5
Explanation:
So the oxidation number of S in Na2S4O6is +2.5.
Answer:
Explanation:
Niels Bohr was a Danish physicist who proposed the hydrogen atom quantum model to explain the discontinuity of the atom's emission spectra.
In <em>Bohr hydrogen atom</em> model, the electrons occupy orbits identified with the numbers <em>n = 1, 2, 3, 4</em>, ... Each number (orbit) corresponds to a different energy level or state. The number n = 1 corresponds to the lowest energy level, and each higher number corresponds to a higher energy level.
This table shows the relative energy of the different orbits of the <em>Bhor hydrogen atom</em><em>:</em>
Orbit Quantum Energy Relative
number level energy
First n = 1 1 E₁
Second n = 2 2 2E₁
Third n = 3 3 9E₁
Fourth n = 4 4 16E₁
Fifth n = 5 5 25E₁
Sixth n = 6 6 36E₁
Seventh n = 7 7 49E₁
When an electron jumps from a higher energy state down to a lower energy state, it emits a photon with an energy equal to the difference of the energies between the initial and the final states.
Since the <u>n = 6 to n = 1</u> transition results in the higher relative energy difference (36E₁ - E₁ = 35E₁), you conclude that it is this transition which results in <u><em>the emission of the highest-energy photon,</em></u><em> which is the option A. </em>