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Marizza181 [45]
2 years ago
11

a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the fo

rce on the charge​
Physics
1 answer:
Roman55 [17]2 years ago
3 0

The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

To calculate the force on a charge in an electric field, we make use of the formula below.

<u>Formula</u>

F = E×Q .......................... Equation 1

Where:

  • F = Force on the charge
  • E = Electric Field
  • Q = charge

From the question,

Given:

  • E = 200 N/C
  • Q = -0.06 C

Substitute these values into equation 1

  • F = 200(-0.06)
  • F = -12 N

Note: The negative sign indicates that the force is in the direction negative of the electric field.

Hence, The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

Learn more about Electric Field here: brainly.com/question/14015797

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A body moves due north with velocity 40 m/s. A force is applied
marshall27 [118]

Answer:

the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

Explanation:

The change in the momentum of a body, if the mass of the body is constant, is given by the following formula:

\Delta p=\Delta (mv)\\\\\Delta p=m\Delta v

p: momentum

m: mass

\Delta v:  change in the velocity

The sign of the change in the velocity determines the direction of rate of change. Then you have:

\Delta v=v_2-v_1

v2: final velocity = 35m/s

v1: initial velocity = 40m/s

\Delta v =35m/s-40m/s=-5m/s

Hence, the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

4 0
3 years ago
An object with a velocity of
algol [13]

Answer:

v = 1.7 m/s

Explanation:

Given that,

Initial velocity of the object, u = 1 m/s

Acceleration of the object, a = 1 m/s²

We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.

v^2-u^2=2ad\\\\v^2=2ad+u^2\\\\v^2=2(1)(1)+1^2\\\\v=\sqrt3\\\\v=1.7\ m/s

So, the final velocity of the object is 1.7 m/s.

4 0
4 years ago
You are traveling in a convertible with the top down. The car is moving at a constant velocity 22.5 m/s, due east along flat gro
Ray Of Light [21]

Answer:

The car moved a distance x=48.6m .

Explanation:

First we need to know: <em>How much time will the tomato spend in the air?</em>

From Kinematics: v_y(t)=v_0_y+at

where v_0_y=10.6\frac{m}{s} and a=-g=-9.8\frac{m}{s^2} is gravity's acceleration.

v_y(t)=v_0_y-gt

When the tomato touches the car again, v_y=-v_0_y=-10.6\frac{m}{s}

Then, we have:

t=\frac{v_y-v_o_y}{-g} ⇒ t=\frac{v_y-v_o_y}{-g}=2.16s

Also from Kinematics we have: x(t)=v_xt

Which is very simple because we can take initial position 0 and there's no acceleration in the x direction. And v_x=22.5\frac{m}{s}

So, taking t=2.16s

x=48.6m

3 0
3 years ago
In the early 1900's ____
Korvikt [17]

Answer:

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Explanation:

he built the first ford

7 0
3 years ago
Why would a dewar flask not need a lid?
snow_tiger [21]

Answer:

because it does ent

Explanation:

5 0
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