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Marizza181 [45]
2 years ago
11

a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the fo

rce on the charge​
Physics
1 answer:
Roman55 [17]2 years ago
3 0

The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

To calculate the force on a charge in an electric field, we make use of the formula below.

<u>Formula</u>

F = E×Q .......................... Equation 1

Where:

  • F = Force on the charge
  • E = Electric Field
  • Q = charge

From the question,

Given:

  • E = 200 N/C
  • Q = -0.06 C

Substitute these values into equation 1

  • F = 200(-0.06)
  • F = -12 N

Note: The negative sign indicates that the force is in the direction negative of the electric field.

Hence, The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

Learn more about Electric Field here: brainly.com/question/14015797

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Red light of wavelength 633 nmnm from a helium-neon laser passes through a slit 0.400 mmmm wide. The diffraction pattern is obse
erik [133]

Answer:

a

 y_1 = 0.004589 \ m

b

 y_2 =0.009179 \  m

Explanation:

From the question we are told that

   The wavelength of the red light is  \lambda _r  = 633 \ nm  =  633 *10^{-9} \  m

    The width of the slit is  d = 0.40 mm = 0.40 *10^{-3} \  m

    The distance of the screen from the point of diffraction is D  =  2.9 \  m

Generally the width of the central bright fringe is mathematically represented as

       y_1 = \frac{\lambda * D}{d}

=>    y_1 = \frac{633 *10^{-9} * 2.90 }{0.40 *10^{-3}}

=>    y_1 = 0.004589 \ m

Generally the width of the first bright fringe on either side of the central one is mathematically represented as

     y_2 = 2 * y_1

=>   y_2 = 2 * 0.004589

=>   y_2 =0.009179 \  m

3 0
3 years ago
Electrons are ejected from sodium metal by any light that has a wavelength shorter than 544 nm. What is the kinetic energy of an
wel

Answer:

KE=2.3 x 10⁻¹⁹ J

Explanation:

Given that

λ = 544 nm

λ' = 485 nm

The kinetic energy KE given as

KE= E - Ф

Where

E=\dfrac{hC}{\lambda'}

\phi=\dfrac{hC}{\lambda}

h= 6.626 x 10⁻³⁴

C=3 x 10⁸ m/s

Now by putting the values

KE=\dfrac{hC}{\lambda'}-\dfrac{hC}{\lambda}

KE=\dfrac{34.34\times 10^{-34}\times 3\times 10^8}{485\times 10^{-9}}- \dfrac{34.34\times 10^{-34}\times 3\times 10^8}{544\times 10^{-9}}

KE=2.3 x 10⁻¹⁹ J

This is kinetic energy.

6 0
3 years ago
Consulting your data table, choose the date that the Moon is closest to the Descending Ecliptic. Note that the Descending Node i
Alenkinab [10]
Found the choices that accompanied this question.

The date that the Moon is closest to the Descending Ecliptic based on the data table is JANUARY 1, 2017.

The date that the Moon is closest to the Ascending Ecliptic based on the data table is JANUARY 16, 2017.

 The Ecliptic Longitude oF the Moon when it is nearest<span>to the descending node is 322 degrees.</span>
6 0
3 years ago
Adam observed properties of four different waves and recorded observations about the frequency and volume of each one in his cha
butalik [34]
I believe this answer is B but my believing sucks so
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3 years ago
At its peak, a tornado is 60.0 m in diameter and carries 500 km/h winds. what is its angular velocity in revolutions per second?
hoa [83]

The speed of the winds corresponds to the tangential velocity of the tornado. Let's convert it into m/s:

v=500 km/h=500 \frac{km}{h} \frac{1000 m/km}{3600 s/h}=138.9 m/s


The diameter of the tornado is d=60.0 m, so its radius is r=d/2=30.0 m


The angular velocity is related to the tangential velocity by:

\omega=\frac{v}{r}=\frac{138.9 m/s}{30.0 m}=4.63 rad/s


And keeping in mind that 1 revolution corresponds to 2 \pi radians, we find the angular velocity in revolutions per second:

\omega=4.63 \frac{rad}{s} (\frac{1}{2 \pi} rev/rad )=0.74 rev/s

4 0
3 years ago
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