Ok i will answer for real this time. Please give me brainliest.
<span>The Answerr is:
5.12*10^15. Since e=h*f, f=e/h. 3.4*10^(-18)/h.
</span>i am so sorry i was doing a challenge and i needed answers to get 100 pts.
Hope I Helped
~TeenOlafLover <3
The answer is A. The outer lines change as it moves
Answer:
They will not meet
h-hX=1.2*g*t²
hX=v0*t-(1/2*g*t²)
Explanation:
fall h=1/2*g*t²
elevation time if v0=20 m/s te=v0/g=20 m/s /9.81 m/s²=2.0387s
hmax=v0²/(2*g)=(400 m²/s²)/19.62 m/s²2=20.387 m
free fall
t=2.0387s yields hX=1/2*g*t²=20.387 m
h-hX=200m - 20.387 m=179,613 m.
so, the second body has not enough initianoal speed to reach a meeting point
Answer:
The velocity of the ball when it first hit the net is Vi= 106.97 m/s
Explanation:
Vf= 0
Vi= ?
a= 56.3 m/s²
t= 1.9 s
Vf= Vi - a*t
Vi= a*t
Vi= 106.97 m/s
Answer:
Explanation:
We know that at pointed corner of a conductor , charge accumulate ie electric field is maximum . Ar pointed corner , radius of curvature will be least . That is why charge leakage is greatest at pointed corner of a charged conductor.
a ) Electric field will be 26.0 kN/C at the point where radius of curvature is greatest .
b ) So electric field will be 66 kN /C at the point where radius of curvature is smallest .
