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Marizza181 [45]
2 years ago
11

a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the fo

rce on the charge​
Physics
1 answer:
Roman55 [17]2 years ago
3 0

The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

To calculate the force on a charge in an electric field, we make use of the formula below.

<u>Formula</u>

F = E×Q .......................... Equation 1

Where:

  • F = Force on the charge
  • E = Electric Field
  • Q = charge

From the question,

Given:

  • E = 200 N/C
  • Q = -0.06 C

Substitute these values into equation 1

  • F = 200(-0.06)
  • F = -12 N

Note: The negative sign indicates that the force is in the direction negative of the electric field.

Hence, The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

Learn more about Electric Field here: brainly.com/question/14015797

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Some sports or activities you can do to improve your overall health and how physical activity can improve your
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Answer:

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3 years ago
An object is moving east, and its velocity changes from 65 m/s to 25 m/s in 10 seconds Which describes the acceleration?
Rasek [7]

Answer:

4 m/s in negative acceleration

Explanation:

Acceleration = V- U/t

Where V is the final velocity

U is the initial velocity and t is the time given.

U = 65 m/s

V= 25 m/s

T= 10 seconds

Acceleration= (25m/s - 65m/s)÷10secs

= - 40/10

= -4m/s^2

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8 0
3 years ago
A 15.0-m uniform ladder weighing 500 N rests against a frictionless wall. The ladder makes a 60.08 angle with the horizontal. (a
grigory [225]

Answer:

a)  fr = 266.92 N,   fy = 1300 N,  b)    μ = 0.36

Explanation:

a) This is a balancing act.

Let's write the rotational equilibrium relations, where the turning point is the bottom of the ladder and the counterclockwise rotations are positive

             -w x - W x₂ + R y = 0         (1)

usemso trigonometry to find distances

            cos 60.08 = x / 7.5

            x = 7.5 cos 60.08

            x = 3.74 m

fireman

           cos 60.08 = x₂ / 4

           x2 = 4 cos 60

           x2 = 2 m

wall support

           sin 60.08 = y / 15

           y = 15 are 60.08

           y = 13 m

we substitute in equation 1

           R y = w x + W x2

            R = (w x + W x2) / y

            R = (500 3.74 +800 2) / 13

            R = 266.92 N

now let's write the expressions for the translational equilibrium

X axis

           R -fr = 0

           R = fr

           fr = 266.92 N

Y Axis  

           Fy - w-W = 0

           fy = 500 + 800

           fy = 1300 N

b) ask the friction coefficient

the firefighter's distance is

          cos 60.08 = x₃ / 9.00

          x₃ = 9 cos 60

          x₃ = 5.28 m

from equation 1

          R = (w x + W x₃) / y

          R = 500 3.74 + 800 5.28) / 13

          R = 468.769 N

we saw that

          fr = R = 468.769

The expression for the friction force is

          fr = μ N

in this case the normal is the ratio to pesos

        N = Fy

       N = 1300 N

        μ N = fr

        μ = fr / N

        μ = 468,769 / 1300

         μ = 0.36

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Ello hace que el humano requiera para su desarrollo de un acompañamiento absoluto por parte de su madre en el período inicial de su vida, tanto para alimentarlo como para transmitirle las nociones básicas de supervivencia; y posteriormente requiera de un entorno social idóneo que le permita desarrollarse emocionalmente para poder vivir normalmente en sociedad.

Además, respecto de sus características físicas, necesita también aprender a caminar, movilizarse y demás atributos físicos que le garanticen un normal desarrollo motor, con lo cual es fundamental que dicha enseñanza provenga también del entorno que lo rodea.

7 0
3 years ago
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