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Marizza181 [45]
2 years ago
11

a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the fo

rce on the charge​
Physics
1 answer:
Roman55 [17]2 years ago
3 0

The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

To calculate the force on a charge in an electric field, we make use of the formula below.

<u>Formula</u>

F = E×Q .......................... Equation 1

Where:

  • F = Force on the charge
  • E = Electric Field
  • Q = charge

From the question,

Given:

  • E = 200 N/C
  • Q = -0.06 C

Substitute these values into equation 1

  • F = 200(-0.06)
  • F = -12 N

Note: The negative sign indicates that the force is in the direction negative of the electric field.

Hence, The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

Learn more about Electric Field here: brainly.com/question/14015797

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A firecracker breaks up into two pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0 m/
larisa [96]

Answer:

Total momentum, p = 21.24 kg-m/s

Explanation:

Given that,

Mass of first piece, m_1=200\ g= 0.2\ kg

Mass of the second piece, m_2=300\ g= 0.3\ kg

Speed of the first piece, v_1=82\ m/s (along x axis)

Speed of the second piece, v_2=45\ m/s (along y axis)

To find,

The total momentum of the two pieces.

Solve,

The total momentum of two pieces is equal to the sum of momentum along x axis and along y axis.

p_x=m_1v_1

p_x=0.2\ kg\times 82\ m/s

p_x=16.4\ kg-m/s

p_y=m_2v_2

p_y=0.3\ kg\times 45\ m/s

p_y=13.5\ kg-m/s

The net momentum is given by :

p=\sqrt{p_x^2+p_y^2}

p=\sqrt{16.4^2+13.5^2}

p = 21.24 kg-m/s

Therefore, the total momentum of the two pieces is 21.24 kg-m/s.

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