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MaRussiya [10]
3 years ago
9

Which diagram shows diffraction as light passes through an opening?

Physics
2 answers:
Lena [83]3 years ago
4 0

Answer:b

Explanation:

Your welcome

Bingel [31]3 years ago
3 0
I don’t see the diagram
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During soccer practice, Maya kicked a soccer ball 37° off the ground at 25 m/s. What was the ball's speed 2.2 s after she kicked
ki77a [65]

<u>Answer</u>

3.44 m/s


<u>Explanation</u>

The motion apply the equations of Newton's law of motion. The ball is acceleration is -9.8 m/s² (acceleration due to gravity. It is negative because the ball is going against gravity, so it is decelerating).

The first equation of Newton's law of motion is;

V = U + at

Where V is the final velocity, U is the initial velocity, a is acceleration and t the time taken.

V = 25 + (-9.8 × 2.2)

    = 25 - 21.56

     = 3.44 m/s

5 0
3 years ago
Shawn and his bike have a total mass of
Trava [24]

Answer:

Shawn's kinetic energy is 61.45 J.

Explanation:

Given;

Mass of the system is, m=52.3\ kg

Displacement of the bike is, d=1.6\ km=1.6\times 1000=1600\ m

Time taken is, t=17.4\ min=17.4\times 60=1044\ s

Let the constant velocity be v.

For constant velocity, magnitude of velocity is given as distance by time.

Therefore, v=\frac{d}{t}=\frac{1600}{1044}=1.533\ m/s

Now, kinetic energy of a body is given as:

KE=\frac{1}{2}mv^2

Here, m=52.3\ kg,\ v=1.533\ m/s

\therefore KE=\frac{1}{2}\times 52.3\times (1.533)^2\\KE=0.5\times 52.3\times 2.35\\KE=61.45\ J

Therefore, Shawn's kinetic energy is 61.45 J.

3 0
3 years ago
How much power is needed to move a 2000 kg mass from the bottom of the 150 m talk great pyramid in Egypt up a ramp if the ramp h
docker41 [41]

Answer:

How Heavy? More than 2,300,000 limestone and granite blocks were pushed, pulled, and dragged into place on the Great Pyramid. The average weight of a block is about 2.3 metric tons (2.5 tons).

Explanation:

4 0
3 years ago
On a winter day with a temperature of -10°C, 500g of snow (water ice) is brought inside where the temperature is 18 °C. The snow
Serjik [45]

Answer:

Explanation:

Mass of ice m = 500g = .5 kg

Heat required to raise the temperature of ice by 10 degree

= mass of ice x specific heat of ice x change in temperature

= .5 x 2093 x 10 J

10465 J

Heat required to melt the ice

= mass of ice x latent heat

0.5 x 334 x 10³ J

167000 J

Heat required to raise its temperature to 18 degree

= mass x specific heat of water x rise in temperature

= .5 x 4182 x 18

=37638 J

Total heat

=10465 +167000+ 37638

=215103 J

7 0
3 years ago
PLEASE HELP ME WITH THIS ONE QUESTION
Ipatiy [6.2K]

k = \dfrac{ (\dfrac{h}{ \lambda}  )^{2} }{2m}

k = (6.626×10-¹⁹/590 × 10-⁹ )^{2} /2 × 1.673 × 10-²⁷

k = (1.12 × 10-³⁰)^2/3.346×10-²⁷

k = 1.25 × 10-⁶⁰ /3.346×10-²⁷

k = 0

ldk why, my answer is coming this :(

4 0
3 years ago
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