The lowest energy of electron in an infinite well is 1.2*10^-33J.
To find the answer, we have to know more about the infinite well.
<h3>What is the lowest energy of electron in an infinite well?</h3>
- It is given that, the infinite well having a width of 0.050 mm.
- We have the expression for energy of electron in an infinite well as,


- Thus, the lowest energy of electron in an infinite well is,

Thus, we can conclude that, the lowest energy of electron in an infinite well is 1.2*10^-33J.
Learn more about the infinite well here:
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Given :
Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connected with wires as shown in the circuit given in figure. The current flowing in both the circuits is the same.
To Find :
Will the heat produced in both the cases be equal.
Solution :
Heat released is given by :
H = i²Rt
Here, R is resistance and is given by :

So,
Now, in the question every thing is constant except for the length of the wire and from above equation heat is directly proportional to the length of the wire.
So, heat produced by Reem's wire is more than Nain one.
Hence, this is the required solution.
The common<span> feature is that the atoms of </span>all elements<span> consist of electrons, protons, and neutrons. Hope this helps!</span>
Answer:
a = -1 m/s^2
Explanation:
Vi = 75 m/s
Vf = 25 m/s
t = 50 s
Plug those values into the following equation:
Vf = Vi + at
25 = 75 + 50a
---> a = -1 m/s^2
Answer:
work done is -150 kJ
Explanation:
given data
volume v1 = 2 m³
pressure p1 = 100 kPa
pressure p2 = 200 kPa
internal energy = 10 kJ
heat is transferred = 150 kJ
solution
we know from 1st law of thermodynamic is
Q = du +W ............1
put here value and we get
-140 = 10 + W
W = -150 kJ
as here work done is -ve so we can say work is being done on system