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3 years ago

Q¹=0,07Mc Q²=2C r=1,08 cm F=.......?

1 answer:

5 0

The force (F) of attraction or repulsion between two point charges (Q1 and Q2) is given by the following rule:
F = (k * q1 * q2) / (r^2) where:
q1 and q2 are the charges
k is coulomb's constant = 9 x 10^9 N. m2/ C2
r is the distance between the two charges.

Applying the givens in the mentioned equation, we find that:
F = (9 x 10^9 x 0.07 x 10^6 x 2) / (0.0108)^2 = 1.08 x 10^19 n

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The difference is that physical weathering is a process that weathers rock without a chemical reaction or change. Chemical weathering changes the identity of rocks and it involves a chemical reaction or change.

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3 years ago

If we ignore air resistance, a falling body will fall 16t2 feet in t seconds. What is the average velocity between t

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Answer:

262.4 m/s

Explanation:

The complete question is

If we ignore air resistance, a falling body will fall 16t^2 feet in t seconds. What is the average velocity between t=8 and t=8.4? Round your answer to two decimal places if necessary.

The distance fallen s = 16t^2

The velocity v = $\frac{ds}{dt}$ = 32t

If we substitute the values of t into the velocity v, we'll have

at t = 8 s, V1 = 32 x 8 = 256 m/s

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3 years ago

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2 years ago

on a distant planet a freely falling object has an acceleration of 20 m/s.^2 what speed will a body dropped from rest on his pla

N76 [4]

Answer:

30 m/s

Explanation:

Vf = ?

Vi = 0 m/s

a = 20 m/s^2

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Plug those values into the equation: Vf = Vi + at

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2 years ago

A hair dryer draws 11 A when it is connected to 120 V. If electrical energy costs $ 0.09/kW·h, what is the cost of using the hai

Papessa [141]

Answer:

The cost of using the hair dryer for 15 minutes is $\$3.6\bar 6$

Explanation:

The parameters given in the question are;

The electric current drawn by the the air dryer, I = 11 A

The voltage to which the hair dryer is connected, V = 120 V

The duration of usage of the hair dryer = 15 minutes = 60 minutes /4 = 1 hour/4 = 0.25 hour

The electrical energy costs $0.09/kW·h

The power consumed by the hair dryer = I × V = 11 × 120 = 1320 Watts = 1.32 kW

The energy used by the hair dryer in 15 minutes (0.25 hour) = 1.32 × 0.25 0.33 kW·h

The energy used by the hair dryer in 15 minutes (0.25 hour) = 0.33 kW·h

The energy cost = $0.09/(kW·h)

Therefore;

The cost of using the hair dryer for 15 minutes (0.25 hour) = 0.33 kW·h/($0.09/(kW·h)) = $33/9 = $3 2/3 = $3.6 $\bar 6$ .

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2 years ago