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4 years ago

12

Q¹=0,07Mc Q²=2C r=1,08 cm F=.......?

1 answer:

Nostrana [21]4 years ago

5 0

The force (F) of attraction or repulsion between two point charges (Q1 and Q2) is given by the following rule:
F = <span>(k * q1 * q2) / (r^2) where:
</span>q1 and q2 are the charges
k is coulomb's constant = 9 x 10^9<span> N. m</span>2/ C<span>2
</span>r is the distance between the two charges.

Applying the givens in the mentioned equation, we find that:
F = (9 x 10^9<span> x 0.07 x 10^6 x 2) / (0.0108)^2 = 1.08 x 10^19 n </span>

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3 years ago

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dimaraw [331]

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If the pitched ball was traveling 77 mph before stanton's bat hit it and 120 mph after his bat hit it, by what amount did the sp

Mice21 [21]

here we will use the concept of Newton's III law

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So here we will say

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3 years ago

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UNO [17]

Part a)

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now the cost will be given

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3 years ago