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trasher [3.6K]
3 years ago
10

How do you calculate the acceleration of an object moving in a straight line

Physics
1 answer:
notka56 [123]3 years ago
5 0

To determine the acceleration of an object moving in a straight line, you must calculate the change in its stored during each unit

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Yanka [14]
Is there information in the previous question which relates to this one?
8 0
3 years ago
Which statements are true for two oppositely charged, isolated parallel plates: C=capacitance, U=stored energy (Q and -Q = charg
vlada-n [284]

Answer:

Explanation:

1) True. The stored energy (U) is proportional to the electric field strength (E). The electric field strength decreases when a dielectric is introduced hence inserting a dielectric decreases U.

2) False. From the formula C=\frac{Q}{V}=\frac{Q}{Vd}, capacitance is inversely proportional to distance hence if the distance is doubled, capacitance decreases.

3) False. As the distance between the electric field and the object increases, its electric field decreases.

4) False. If a dielectric is inserted, the plates are further separated. Q stays the same.

5) True. The electric field strength decreases when a dielectric is introduced and  capacitance is inversely proportional to electric field hence Inserting a dielectric increases C

6) True. If a dielectric is inserted, the plates are further separated. Q stays the same.

7) True. When the distance is doubled, U increases

7 0
3 years ago
I need help on this question
raketka [301]

Answer:

there are 5 hydrogen atoms in that formula

3 0
3 years ago
Read 2 more answers
A 10 m long steel beam is accidentally dropped by a construction crane from a height of 4.89 m. The horizontal component of the
Otrada [13]

Answer:

e = 1.21 mV

Explanation:

given,                                

length of rod = 10 m                

height of drop = 4.89 m          

Earth’s magnetic field =  12.4 µT

acceleration of gravity = 9.8 m/s²

velocity of the beam                      

v = \sqrt{2gh}

v = \sqrt{2\times 9.8 \times 4.89}

v = 9.79 m/s                        

emf of the beam

e = B l v                              

e = 12.4 x 10⁻⁶ x 9.79 x 10

e = 1.21 x 10⁻³ V

e = 1.21 mV

4 0
3 years ago
A man of mass 70 kg climbs stairs of vertical height 2.5m. Calculate the work done against the force of gravity. (Take g = 9.81
Alona [7]

Answer:

1716.75 J

Explanation:

<u>Step </u><u>1</u><u>:</u> First check what we are provided with. As per given question we have:

mass (m) = 70 kg, height (h) = 2.5 m and acceleration due to gravity (g) = 9.81 m/s².

<u>Step</u><u> </u><u>2</u><u>:</u> Check what we are asked to find out.

Work done = Change in Potential energy

The stuff required to solve this question is potential energy. Using the formula: P = mgh. Where P is Potential energy, m is mass, g is acceleration due to gravity and h is height.

<u>Step</u><u> </u><u>3</u><u>:</u> Substitute the known values in the above formula.

→ P = 70 × 2.5 × 9.81

→ P = 1716.75 J

Hence, the work done against the force of gravity is 1716.75 J.

3 0
2 years ago
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