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trasher [3.6K]
3 years ago
10

How do you calculate the acceleration of an object moving in a straight line

Physics
1 answer:
notka56 [123]3 years ago
5 0

To determine the acceleration of an object moving in a straight line, you must calculate the change in its stored during each unit

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The acceleration due to gravity on earth is 9.8 m/s2. what is the weight of a 75 kg person on earth
erastovalidia [21]
Weight = mass * gravity
W = 75 kg * 9.8
W = 735 N

hope this  helps :)
5 0
3 years ago
Guys help me with this question.​
sleet_krkn [62]

Answer:

Explanation:

Brownian motion is a random (irregular) motion of particles e.g smoke particle. The set up in the diagram can be used to observe the motion of smoke.

1. The apparatus used are:

A is a source of light

B is a converging lens

C is a glass smoke cell

D is a microscope

2. The uses of the apparatus are:

A - produces the light required to so as to see clearly the movement of the particles.

B - converges the rays of light from the source to the smoke cell.

C - is made of glass and used for encamping the smoke particles so as not to mix with air.

D - is used for the clear view or observation or study of the motion of the smoke particles in the cell.

4 0
3 years ago
What is the value for the kinetic energy for a n = 5 Bohr orbit electron in zeptoJoules?
Ne4ueva [31]

Answer:

The kinetic energy is 86.6 zepto joules.

Explanation:

Given that,

Number of orbit n =5

We know that,

Bohr's radius for hydrogen atom is

r = 0.53\times10^{-10}\times n^2\ m

Now, put the value of n in the formula of radius

r=0.53\times10^{-10}\times5^2

r =1.33\times10^{-9}\ m

We need to calculate the kinetic energy

Using formula of kinetic energy

E_{k}=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{e^2}{2\times r_{s}}

Put the value into the formula

E_{k}=\dfrac{9\times10^{9}\times(1.6\times10^{-19})^2}{2\times1.33\times10^{-9}}

E_{k}=8.66\times10^{-20}\ J

We know that,

1\ zepto\ joule=1\times10^{-21}\ J

The kinetic energy is

E_{k}=\dfrac{8.66\times10^{-20}}{1\times10^{-21}}

E_{k}=86.6\ zepto\ Joules

Hence, The kinetic energy is 86.6 zepto joules.

8 0
3 years ago
An aluminum cup of 150 cm3 capacity is completely filled with glycerin at 23°C. How much glycerin will spill out of the cup if t
AVprozaik [17]

Answer:

1.19cm^3 of glycerine

Explanation:

Let Vo= 150cm^3 for both aluminum and glycerine, using expansion formula:

Volume of spill glycerine = change in volume of glycerine - change in volume of aluminum

Volume of glycerine = coefficient of volume expansion of glycerine * Vo* change in temperature - coefficient of volume expansion of Aluminum*Vo* change temperature

coefficient of volume expansion of aluminum = coefficient of linear expansion of aluminum*3 = 23*10^-6 * 3 = 0.69*10^-4 oC^-1

Change in temperature = 41-23 = 18oC

Volume of glycerine that spill = (5.1*10^-4) - (0.69*10^-4) (150*18) = 4.41*10^-4*2700 = 1.19cm3

3 0
2 years ago
John argues that energy is not conserved because when someone presses the brakes in a moving car, kinetic energy is lost. What s
babunello [35]
kinetic energy is converted into elastic potential energy stored in the brakes.
7 0
2 years ago
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