<h3>
Answer:</h3>
14 milliliters
<h3>
Explanation:</h3>
We are given;
Prepared solution;
- Volume of solution as 0.350 L
- Molarity as 0.40 M
We are required to determine the initial volume of HNO₃
- We are going to use the dilution formula;
- The dilution formula is;
M₁V₁ = M₂V₂
Rearranging the formula;
V₁ = M₂V₂ ÷ M₁
=(0.40 M × 0.350 L) ÷ 10.0 M
= 0.014 L
But, 1 L = 1000 mL
Therefore,
Volume = 14 mL
Thus, the volume of 10.0 M HNO₃ is 14 mL
Answer: The de broglie wavelength is 
.
Explanation:
Calculate 
as follows.
where,
h = plank's constant = 
p = momentum = 
Putting the values in the formula as follows.
= 
=
Thus, the de broglie wavelength is .
I think it's Chlorine but, not 100% sure. so C.
The conductance of the electric current through the electrolytic solution increases with increase in concentration.
<h3>
What is electrolytic solution?</h3>
Electrolytic solutions are solutions that are capable of conducting an electric current due to presence of ions.
The current flowing in an Electrolytic solutions is calculated as;
Q = It
I = Q/t
where;
Increase in the concentration of the charges, increases the amount of charges in the solution and hence the conductance of the solutions will increase as well.
Learn more about Electrolytic solutions here: brainly.com/question/14654936
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I will present a simple reaction so we can do this conversion:
2H₂ + O₂ → 2H₂O
We will assume we have 32 g of O₂ and we want to find the amount of water, assuming this reaction goes to completion. We must first convert the initial mass to moles, which we do using the molar mass in units of g/mol. The molar mass of O₂ is 32 g/mol.
32 g O₂ ÷ 32 g/mol = 1 mole O₂.
Now that we have moles of oxygen, we use the molar coefficients to find the ratio of water molecules to oxygen molecules. We can see there are 2 moles of water for every 1 mole of oxygen.
1 moles O₂ x (2 mol H₂O/ 1 mol O₂) = 2 moles H₂O
Now that we have the moles of water, we can convert this amount into grams using the molar mass of water, which is 18 g/mol.
2 moles H₂O x 18 g/mol = 36 g H₂O
Now we have successfully converted the mass of one molecule to the mass of another.
