To identify the amount of chloride ions present in 0.1 mol
of MgCl2, first know the amount of mols of Chloride. The answer is 0.2 mol
since you just need to multiply 0.1 to 2 because there are 2 chloride in the
compound. Then, multiply the mols to 6.02x10^23. The answer would be
1.204x10^23 chloride ions.
MO Diagram of C₂⁻ is shown below,
Bond order is calculated as,
Bond Order = [# of e⁻s in BMO]-[#of e⁻s in ABMO] / 2
Where,
BMO = Bonding Molecular Orbital
ABMO = Anti-Bonding Molecular Orbital
Putting values,
Bond Order = [9]-[4] / 2
Bond Order = 5 / 2
Bond Order = 2.5
Answer:
calcium ca
Explanation:
We can see here that the only element that is on the same group (column) as Ba (Barium) is Calcium (Ca).
The following compounds and the number and type of ions are as follows:
Gold and chloride:
Gold (III) = Au 3+
Chloride = Cl 1-
Calcium and Sulfate:
Calcium Sulfate:
Calcium = Ca 2+
Sulfate = SO4 2-
Magnesium and Hydroxide
Magnesium Hydroxide: Mg(OH)2
Magnesium: Mg 2+
Hydroxide: (OH) 1-