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Pavel [41]
3 years ago
7

6. Steel is a metallic-like material but it is not a pure element. It is a alloy.

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

true

hope this helps! have an amazing day!

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Based on the chart, which food chain best models a flow of energy in this ecosystem?
GarryVolchara [31]

Answer:

B

Explanation:

8 0
3 years ago
When there are more electrons than protons an object has an overall<br> charge.
azamat

Answer:it would have a negative charge because  electrons are negative

Explanation:

7 0
3 years ago
From the balanced reaction:
Lelu [443]

Answer:

The mass of O₂ that will be needed to burn 36.1 g B₂H₆ is 125.29 g.

7 0
2 years ago
Given the reaction: 4A1 + 302 - 2A1,O, How many grams of Al will be
dlinn [17]

Answer:

The answer to your question is 27 g of Al

Explanation:

Data

mass of Al = ?

moles of Al₂O₃ = 0.5

The correct formula for the product is Al₂O₃

Balanced chemical reaction

               4Al + 3O₂   ⇒   2Al₂O₃

Process

1.- Calculate the molar mass of the product

Al₂O₃ = (27 x 2) + (16 x 3)

         = 54 + 48

         = 102 g

2.- Convert the moles of Al₂O₃ to grams

               102 g ---------------- 1 mol

                 x       ----------------  0.5 moles

                 x = (0.5 x 102) / 1

                 x = 51 g of Al₂O₃

3.- Use proportions to calculate the mass of Al

                4(27) g of Al --------------- 2(102) g of Al₂O₃

                     x               --------------- 51 g

                        x = (51 x 4(27)) / 2(102)

                        x = 5508 / 204

                        x = 27 g of Al

4 0
3 years ago
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb ( NO 3 ) 2
nikklg [1K]

Answer : The volume of NH_4I solution required is, 2.93 L

The number of moles of PbI_2 formed from the reaction is, 0.662 moles.

Explanation :

First we have to calculate the initial moles of Pb(NO_3)_2.

\text{Moles of }Pb(NO_3)_2=\text{Concentration of }Pb(NO_3)_2\times \text{Volume of solution}

\text{Moles of }Pb(NO_3)_2=0.700M\times 0.945L=0.662mol

Now we have to calculate the moles of NH_4I

The balanced chemical reaction is:

Pb(NO_3)_2(aq)+2NH_4I(aq)\rightarrow PbI_2(s)+2NH_4NO_3(aq)

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react with 2 moles of NH_4I

So, 0.662 mole of Pb(NO_3)_2 react with 0.662\times 2=1.32 moles of NH_4I

Now we have to calculate the volume of NH_4I

\text{Volume of }NH_4I=\frac{\text{Moles of }NH_4I}{\text{Concentration of }NH_4I}

\text{Volume of }NH_4I=\frac{1.32mol}{0.450mol/L}=2.93L

Now we have to calculate the moles of PbI_2

From the balanced chemical reaction we conclude that,

As, 1 mole of Pb(NO_3)_2 react to give 1 moles of PbI_2

So, 0.662 mole of Pb(NO_3)_2 react to give 0.662 moles of PbI_2

Thus, the number of moles of PbI_2 formed from the reaction is, 0.662 moles.

7 0
3 years ago
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