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3 years ago

Some car batteries give off a potentially explosive mixture of gases. What kind of change is taking place in the battery?

Chemistry

1 answer:

MrMuchimi3 years ago

8 0

It is chemical change.

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What is the gram formula mass of Ca3(PO4)2

Georgia [21]

Mass Molar of $Ca_{3} (PO_4)_2$
Ca = 3*40 = 120 amu
P = 2*31= 62 amu
O = (16*4)*2 = 64*2 = 128 amu
--------------------------------------
Mass Molar of $Ca_{3} (PO_4)_2$ = 120 + 62 + 128 = 310 g/mol

Therefore: <span>What is the gram formula mass of Ca3(PO4)2 ?
</span>Answer: 310 grams

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3 years ago

Why are stars special sources of light?(2 points)

Alex787 [66]

Answer:

They give off their own light energy

Explanation:

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2 years ago

What is the mass of 22.4 L of H2 at STP? (5 points)

cestrela7 [59]

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2 years ago

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A solution of starch at room temperature does not readily decompose to form a solution of simple sugars because

Basile [38]

Explanation:

The starch requires a temperature higher than the room temperature (arround 60 °C) to decompose to form simple sugars. This is because the energy required to break the chemical bonds. Also, it may need the action of some specific enzymes (alpha and beta amilase) to break those bonds.

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3 years ago

1.65g of zinc is used to make 8g of zinc iodide. How much iodine is required for this reaction?

creativ13 [48]

Answer:

6.45 g of iodine, I₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + I₂ —> ZnI₂

Next, we shall determine the mass of Zn and I₂ that reacted from the balanced equation. This can be obtained as follow:

Molar mass of Zn = 65 g/mol

Mass of Zn from the balanced equation = 1 × 65 = 65 g

Molar mass of I₂ = 127 × 2 = 254 g/mol

Mass of I₂ from the balanced equation = 1 × 254 = 254 g

SUMMARY:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Finally, we shall determine the mass of f I₂ needed to react with 1.65 g of Zn. This can be obtained as follow:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Therefore, 1.65 g of Zn will react with = (1.65 × 254)/65 = 6.45 g of I₂.

Thus, 6.45 g of iodine, I₂ is needed for the reaction.

4 0

3 years ago