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12345 [234]
4 years ago
12

The pressure intensity at a point in a fluid is equal in all directions a.true b.false​

Engineering
1 answer:
KIM [24]4 years ago
8 0

Answer:

True

Explanation:

The pressure intensity in a fluid equals in all direction, states Pascal's law. The pressure are forces on the side faces of an element. Transmission of fluid is defined by the pressure exerted on it. The pressure intensity at a point is point where pressure is applied. The fluid is equal in all directions.

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A technique for resolving complex repetitive waveforms into sine or cosine waves and a DC component is known as:
tatiyna

Answer:

(A) Fourier Analysis

Explanation:

Fourier Analysis  

It is the form of study of the way a general functions can be represented via the sum of the simple trigonometric functions .

It is named after Joseph Fourier , who represented a function as a sum of its trigonometric functions and it simplifies the study of the heat transfer .

Hence ,  

The technique for resolving the complex repetitive waveforms into the sine or the cosine waves and the DC component is known as the Fourier Analysis .

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Question about transformers and generators
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woah

Explanation:

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4 years ago
Storm sewer backup causes your basement to flood at the steady rate of 1 in. of depth per hour. The basement floor area is 2600
Wittaler [7]

Answer:

attached below

Explanation:

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3 years ago
Help please? this math is way too difficult
hoa [83]

Answer:

makin this,ill help with your math

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6 0
3 years ago
Oil with a kinematic viscosity of 4 10 6 m2 /s fl ows through a smooth pipe 12 cm in diameter at 2.3 m/s. What velocity should w
Setler79 [48]

Answer:

Velocity of 5 cm diameter pipe is 1.38 m/s

Explanation:

Use following equation of Relation between the Reynolds numbers of both pipes

Re_{5} = Re_{12}

\sqrt{\frac{V_{5}XD_{5}  }{v_{5}}}= \sqrt{\frac{V_{12}XD_{12}  }{v_{12}}}

Re_{5} = Reynold number of water pipe

Re_{12} = Reynold number of oil pipe

V_{5} = Velocity of water 5 diameter pipe = ?

V_{12} = Velocity of oil 12 diameter pipe = 2.30

v_{5} = Kinetic Viscosity of water = 1 x 10^{-6} m^{2}/s

v_{12} = Kinetic Viscosity of oil =  4 x 10^{-6} m^{2}/s

D_{5} = Diameter of pipe used for water = 0.05 m

D_{12} = Diameter of pipe used for oil = 0.12 m

Use the formula

\sqrt{\frac{V_{5}XD_{5}  }{v_{5}}}= \sqrt{\frac{V_{12}XD_{12}  }{v_{12}}}

By Removing square rots on both sides

{\frac{V_{5}XD_{5}  }{v_{5}}}= {\frac{V_{12}XD_{12}  }{v_{12}}}

{V_{5}= {\frac{V_{12}XD_{12}  }{v_{12}XD_{5}\\}}xv_{5}

{V_{5}= [ (0.23 x 0.12m ) / (4 x 10^{-6} m^{2}/s) x 0.05 ] 1 x 10^{-6} m^{2}/s

{V_{5} = 1.38 m/s

4 0
4 years ago
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