Answer:
a) The amount of heat transfer in the regenerator, q = 114.12 kJ/kg
b) Thermal efficiency = 35.9%
Explanation:
The calculations are neatly handwritten and attached as files to this solution for easiness of expression and clarity. The cycle is also drawn on the T - S diagram and included in the attached files. Check the files below for the complete calculation.
I hope this helps!
Answer:
13177.34 J
Explanation:
Work done = force × distance
work done by the engine = kinetic energy + potential energy + work done friction
kinetic energy due to the car's speed = 1/2mv² = 4468.5 J
potential energy due to the height = mgh = 993 kg × 9.8 m/s² × 0.6 m = 5838.84 J
work done by friction = 2870 J
work done by engine = 5838.84 J + 2870 J + 4468.5 J = 13177.34 J
Answer:
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Explanation:
