The answer is d, because the simplest form of C4H10 is C2H5 which is the empirical formula
Answer:
0.97 atm.
Explanation:
From the question given above, the following data were obtained:
Final pressure (P2) = 6.8 atm
Initial temperature (T1) = 40 K
Final temperature (T2) = 280 K
Initial pressure (P1) =?
Thus, we can obtain the initial (original) pressure of the gas as follow:
P1/T1 = P2/T2
P1 /40 = 6.8/280
Cross multiply
P1 × 280 = 40 × 6.8
P1 × 280 = 272
Divide both side by 280
P1 = 272/280
P1 = 0.97 atm
Therefore, the original pressure of the gas is 0.97 atm.
Hello!
To solve this problem we need to know the value of
pKa for HC₂H₃O₂ (Acetic Acid) which is
4,76. Now we can apply the
Henderson-Hasselbach equation, as follows (assuming that HC₂H₃O₂ concentration is 0,22M):
So, the pH for this buffer solution of HC₂H₃O₂ and KC₂H₃O₂ is
4,50Have a nice day!
Answer:
to the right (products side)
Explanation:
The equilibrium constant K describes the ratio between the concentration of products and reactants at equilibrium. For a general reaction:
a A + b B → c C + d D
The equilibrium constant expression is:
A low value of K indicates that the concentration of products (C and D) is low in relation with the concentration of reactants (A and B).
Conversely, a high value of K indicated that the concentration of products is high compared with the concentration of reactants.
Since K = 6.4 × 10⁹ is a high value, the concentration of products is higher than the concentration of reactants at equilibrium. Thus, the position of the equilibrium is favored to the right.
The balanced equation that shows the reaction between oxalic acid and permanganate ion in an acidic medium is: 2MnO4- + 5H2C2O4 + 6H+ -> 2Mn(2+) + 10CO2 + 8H2O. Thus, 1 mole of oxalic acid reacts with 0.4 mole of permanganate ion. This was obtained using stoichiometry:
1 mol H2C2O4 x (2 mol MnO4-/ 5 mol H2C2O4) = 0.4 mol MnO4-
In this redox reaction, the permanganate is reduced to manganese(II) ion.