How many subshells are in the n =4 shell?

Why are animal vaccinated?

juin [17]

Answer:

to go against dangerous viral and bacteria

Explanation:

5 0

3 years ago

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How many moles of chromium III nitrate are produced When chromium reacts with 0.85 moles of lead for nitrate to produce chromium

Pepsi [2]

0.85 moles formula units of lead nitrate will produce 0.57 moles formula units of chromium (III) nitrate.

<h3>Explanation</h3>

Typically, the oxidation state of Pb in lead nitrate tend to be +2. In other words, Pb in lead nitrate tends to exist as $\text{Pb}^{2+}$ ions. The formula for a nitrate ion is ${\text{NO}_3}^{-}$ . The charge on each of the nitrate ion is -1. The charge on the two ions should balance. As a result, each $\text{Pb}^{2+}$ ion in lead nitrate would pair up with two ${\text{NO}_3}^{-}$ ions. The formula for lead nitrate will be $\text{Pb}({\text{NO}_3})_2$ . Each formula unit of lead nitrate will contain one $\text{Pb}^{2+}$ ion and two ${\text{NO}_3}^{-}$ ions.

The "III" in the name "chromium (III) nitrate" is a Roman Numeral. It indicates that the oxidation state of Cr in chromium (III) nitrate is +3. The Cr in that compound will exist as $\text{Cr}^{3+}$ . Similarly, each $\text{Cr}^{3+}$ will pair up with three ${\text{NO}_3}^{-}$ ions. The formula for chromium (III) nitrate will be $\text{Cr}(\text{NO}_3})_3$ . Each formula unit of chromium (III) nitrate will contain one ${\text{NO}_3}^{-}$ ion and three ${\text{NO}_3}^{-}$ ions.

0.85 moles formula units of lead nitrate will contain 0.85 × 2 = 1.7 moles of ${\text{NO}_3}^{-}$ ions. Those nitrate ions will end up in 1.7 / 3 = 0.57 moles formula units of chromium (III) nitrate. As a result, the reaction will produce 0.57 moles formula units of chromium (III) nitrate.

7 0

3 years ago

A sample of nitrogen gas had a volume of 500. ml, a pressure in its closed container of 740 torr and a temperature 25 degrees c

Semenov [28]

Question:
<span>A sample of nitrogen gas had a volume of 500mL, a pressure in its closed container of 740 torr and a temperature of 25°c. what was the volume of gas when the temperature was changed to 50°c and the new pressure was 760 torr?

Answer:

Data Given:
V</span>₁ = 500 mL

P₁ = 740 torr

T₁ = 25 °C + 273 = 298 K

V₂ = ?

P₂ = 760 torr

T₂ = 50 °C + 273 = 323 K

Solution:
Let suppose the gas is acting Ideally, then According to Ideal Gas Equation,

P₁ V₁ / T₁ = P₂ V₂ / T₂

Solving for V₂,

V₂ = (P₁ V₁ T₂) ÷ (T₁ P₂)

Putting Values,

V₂ = (740 torr × 500 mL × 323 K) ÷ (298 K × 760 torr)

V₂ = 527.68 mL

7 0

3 years ago

Calculate the mass of a substance which has a volume of 35

makkiz [27]

The answer is 17.5kg.

To get the mass of an object you do Volume × Density. The SI unit of Mass is "kg."

7 0

3 years ago

Show, in a step by step fashion, your calculations to determine the percent

marusya05 [52]

The percent by volume of a solution : 19.23%

<h3>Further explanation</h3>

Given

50 ml of ethanol

210 ml of water

Required

The percent by volume of a solution

Solution

Percent Volume (% v/v) : volume (ml) of solute/100 ml of solution ⇒ ratio of the volume of the solute to total volume of the solution

$\tt \%solute(v/v)=\dfrac{solute~volume}{solution~volume}\times 100\%$

solute= Ethanol

solvent=water

Solution = solute+solvent

Total volume of the solution :

$\tt =volume~of~Ethanol+solume~of~water\\\\=50~ml+210~ml\\\\=260~ml$

Percent by volume :

$\tt \%volume=\dfrac{50}{260}\times 100\%\\\\\%volume=19.23\%$

8 0

3 years ago