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scoundrel [369]
2 years ago
7

: If you know that a ∝ b and a ∝ c, then you can also say that a ∝ bc, or the product of b and c. Take the above three proportio

nalities (including V ∝ n) and combine them into a single proportionality in the form: V ∝ ? Show your work below.
Chemistry
1 answer:
aleksley [76]2 years ago
3 0

Answer:

V ∝ abc

Explanation:

This task is a joint variation task involving only direct proportionality:

Direct variation is one in which two variables are in direct proportionality to each other. This means that as one increases, the other variable also increases and vice - versa.

Joint variation is one in which one variable is dependent on two or more variables and varies directly as each of them.

In this exercise:

If a ∝ b and a ∝ c, then a ∝ bc

Taking the above three proportionalities,

V ∝ a ∝ b ∝ c

V ∝ a ∝ bc

V ∝ abc

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What mass of hydrogen contains the same number of atoms as 7.00 g of nitrogen
Leto [7]
Molecular mass of nitrogen, N2 = 2*14 = 28
molecular mass of hydrogen, H2=2*1 = 2

Molecules of both elements contain 2 atoms, so the ratio of molecules is the same as the ratio of atoms.

From the molecular masses above, 
ratio of number of molecules = ratio of molecular masses, therefore
7g N2 : x g H2 = 28:2
cross multiply:
x=7*2/28=0.5 g of Hydrogen has the same number of atoms as 7 g of nitrogen (at room temperatures)

7 0
2 years ago
A piece of metal ore has a density of 1.72 g/mL. When a student places it into a graduated cylinder containing water, the liquid
Hunter-Best [27]

Answer:

9g

Explanation:

Since..., Density = mass/volume

;Firstly calculate the volume change of the water when the metal is placed in,

;Volume = 26.47 - 21.25

;Volume = 5.22 mL

Hence the mass of the ore;

; Making mass the subject of formula in the above equation,

Mass = Density × Volume

; Mass = 1.72 × 5.22

; Hence the mass = 8.9784

= 9g

5 0
3 years ago
** ANSWER FAST I WILL MARK YOU BRAINLIEST AND GIVE 20 POINTS * * THIS IS A CHEMISTRY QUESTION SO PLEASE ONLY ANSWER IF YOU ARE G
Anna11 [10]

Answer:

\boxed{\text{ B. Increase the temperature and decrease the pressure.}}

Explanation:

Let's say the reaction is

R ⇌ 2P; endothermic

I like to consider heat as if it were a reactant or a product in a chemical equilibrium.

Another way to write the equilibrium would be

heat + R ⇌ 2P

According to Le Châtelier's Principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

Let's consider each of the stresses in turn.

(i) Changing the temperature

If you want to increase the amount of product, you increase the temperature. The system will try to get rid of the added heat by shifting to the right, thus forming more product.

(ii) Changing the pressure

If R and P are liquids or solids or in aqueous solution, changing the pressure will have no effect. Something must be in the gas phase for a change in pressure to affect the position of equilibrium.

If P is a gas, the equilibrium is

heat + R ⇌ 2P(g)

Then, decreasing the pressure will produce more P. If you reduce the pressure, the system will respond by shifting to the right (the side with more gas molecules) to produce more P and bring the pressure back up

5 0
3 years ago
You want to determine the effect of a certain fertilizer on the growth of orchids grown in a greenhouse.
Aleks [24]
Hypothesis - I predict that the orchids will grow best with a medium concentration of fertilizer
3 0
2 years ago
Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9
EleoNora [17]

Answer : The current passing between the electrodes is, 1.056\times 10^{-2}A

Explanation :

First we have to calculate the charge of sodium ion.

q=ne

where,

q = charge of sodium ion

n = number of sodium ion = 2.68\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C

Now we have to calculate the charge of chlorine ion.

q'=ne

where,

q' = charge of chlorine ion

n = number of chlorine ion = 3.92\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C

Now we have to calculate the current passing between the electrodes.

I=\frac{q}{t}+\frac{q'}{t}

I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}

I=1.056\times 10^{-2}A

Thus, the current passing between the electrodes is, 1.056\times 10^{-2}A

4 0
3 years ago
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