4^4x = 8
since 4 = 2^2 & 8= 2^3
so we can write the equation as
(2^2)^4x = 2^3
2^8x =2^3
sp ,, 8x = 3
then x = 3/8
P E M D A S
Parentheses first:
So, 12 + 4 x 13 - 2
12 + 52 - 2
64 - 2
62
Answer:
A) 3 in
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Geometry</u>
- Surface Area of a Sphere: SA = 4πr²
- Diameter: d = 2r
Step-by-step explanation:
<u>Step 1: Define</u>
SA = 23 in²
<u>Step 2: Find </u><em><u>r</u></em>
- Substitute [SAS]: 23 in² = 4πr²
- Isolate <em>r </em>term: 23 in²/(4π) = r²
- Isolate <em>r</em>: √[23 in²/(4π)] = r
- Rewrite: r = √[23 in²/(4π)]
- Evaluate: r = 1.35288 in
<u>Step 3: Find </u><em><u>d</u></em>
- Substitute [D]: d = 2(1.35288 in)
- Multiply: d = 2.70576 in
- Round: d ≈ 3 in
THE ANSWER IS LYFE 3432423
