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3 years ago

Which type of basin forms at transform boundaries? rift wedge arc strike-slip

Chemistry

2 answers:

Alenkasestr [34]3 years ago

8 0

Strike slip forms at Basin

Blababa [14]3 years ago

4 0

Answer:

Strike slip forms at transform boundaries

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What do isotopes have in common

alexira [117]

Answer:

Isotopes are atoms of the same element that have different numbers of neutrons but the same number of protons and electrons. The difference in the number of neutrons between the various isotopes of an element means that the various isotopes have different masses.

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3 years ago

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Can you help me figure out how to determine the Conjugate Acid of Sodium Chloride - NACL ?

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1 year ago

Find the number of moles in 1.00 x 1023 atoms of chromium.

IRISSAK [1]

Answer:

<h2>0.17 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

$n = \frac{1.00 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{1}{6.02} \\ = 0.166112$

We have the final answer as

<h3>0.17 moles</h3>

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3 years ago

A 5.00 gram sample of an oxide of lead PbxOy contains 4.33 g of lead. Determine simplest formula for the compund

Harrizon [31]

Answer: The empirical formula is $PbO_2$

Explanation:

Mass of Pb = 4.33 g

Mass of O = (5.00-4.33) g = 0.67 g

Step 1 : convert given masses into moles

Moles of Pb = $\frac{\text{ given mass of Pb}}{\text{ molar mass of Pb}}= \frac{4.33g}{207g/mole}=0.021moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{0.67g}{16g/mole}=0.042moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Pb = $\frac{0.021}{0.021}=1$

For O = $\frac{0.042}{0.021}=2$

The ratio of Pb O= 1: 2

Hence the empirical formula is $PbO_2$

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3 years ago

Heat is added to a 200.-gram sample of H2O(s) to melt the sample at 0°C. Then the resulting H2O (image) is heated to a final tem

pochemuha

You are given 200 grams of H2O(s) at an initial temperature of 0°C. you are also given the final temperature of water after heating at 65°C. You are required to get the total amount of heat to melt the sample. The specific heat capacity, cp, of water is 4.186 J/g-°C. Let us say that T1 = 0°C and T2 = 65°C. The equation for heat, Q, is

Q = m(cp)(T2-T1)
Q = 200g(4.186 J/g-°C )(65°C - 0°C)
<u>Q = 54,418J</u>

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3 years ago

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