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devlian [24]
3 years ago
8

M/s

Physics
1 answer:
SashulF [63]3 years ago
8 0

Answer:

a. Final velocity, V = 2.179 m/s.  

b. Final velocity, V = 7.071 m/s.

Explanation:

<u>Given the following data;</u>

Acceleration = 0.500m/s²

a. To find the velocity of the boat after it has traveled 4.75 m

Since it started from rest, initial velocity is equal to 0m/s.

Now, we would use the third equation of motion to find the final velocity.

V^{2} = U^{2} + 2aS

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
  • a represents acceleration measured in meters per seconds square.
  • S represents the displacement measured in meters.

Substituting into the equation, we have;

V^{2} = 0^{2} + 2*0.500*4.75

V^{2} = 4.75

Taking the square root, we have;

V^{2} = \sqrt {4.75}

<em>Final velocity, V = 2.179 m/s.</em>

b. To find the velocity if the boat has traveled 50 m.

V^{2} = 0^{2} + 2*0.500*50

V^{2} = 50

Taking the square root, we have;

V^{2} = \sqrt {50}

<em>Final velocity, V = 7.071 m/s.</em>

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Agata [3.3K]

Answer:

Magnets come in a variety of shapes and one of the more common is the horseshoe (U) magnet. The horseshoe magnet has north and south poles just like a bar magnet but the magnet is curved so the poles lie in the same plane. The magnetic lines of force flow from pole to pole just like in the bar magnet.

7 0
3 years ago
What is the period of a simple pendulum 47 cm long (a) on the Earth, and ( b) when it is in a freely falling elevator?
Liula [17]

Answer:

a)1.37 s

b)∞ ( Infinite)

Explanation:

Given that

L= 47 cm              ( 1 m =100 cm)

L= 0.47 m

a)

On the earth :

Acceleration due to gravity = g

We know that time period of the simple pendulum given as

T=2\pi\sqrt{ \dfrac{L}{g_{{eff}}}

Here

g_{eff}= g

Now by putting the values

T=2\pi \times\sqrt{ \dfrac{0.47}{9.81}}

T=1.37 s

b)

Free falling elevator :

When elevator is falling freely then

g_{eff}= 0            ( This is case of weightless motion)

Therefore

T=2\pi\sqrt{ \dfrac{L}{0}

T=∞  (Infinite)

6 0
3 years ago
Which of the statements given below is correct? 1. In winter, the wind blows from land to oceans. 2. In summer , the winds blow
densk [106]

Answer:

The second one should be correct

3 0
3 years ago
Find the 24th term of the arithmetic sequence 11, 14, 17, … . Express the 24 terms of the series of this sequence using sigma no
Anna71 [15]

Answer:

The 24th term is 80 and the sum of 24 terms is 1092.

Explanation:

Given that,

The arithmetic series is

11,14,17,........24

First term a = 11

Difference d = 14-11=3

We need to calculate the 24th term of the arithmetic sequence

Using formula of number of terms

t_{n}=a+(n-1)d

Put the value into the formula

t_{24}=11+(24-1)\times3

t_{24}=80

t_{24}=u_{24}=80

We need to calculate the sum of the first 24 terms of the series

Using formula of sum,

S_{n}=\dfrac{n}{2}(a+u_{24})

Put the value into the formula

S_{n}=\dfrac{24}{2}\times(11+80)

S_{n}=1092

Hence, The 24th term is 80 and the sum of 24 terms is 1092.

5 0
3 years ago
The 630-nm light from a helium-neon laser irradiates a grating. The light then falls on a screen where the first bright spot is
dimaraw [331]

Answer:

464.8 nm

Explanation:

The second wavelength of light can be calculated using the next equation:

\lambda = \frac{x*d}{L}        

<u>Where:</u>

<em>λ : is the wavelength of light</em>

<em>x: is the distance from the central maximum</em>

<em>d: is the distance between the spots                      </em>

<em>L: is the lenght from the screen to the bright spot</em>

For the first wavelength of light we have:

\lambda_{1} = \frac{x_{1}*d}{L}

630 \cdot 10^{-9} m = \frac{0.61 m*d}{L}

\frac{d}{L} = \frac{630 \cdot 10^{-9} m}{0.61 m} = 1.033 \cdot 10^{-6}  (1)    

For the second wavelength of light we have:

\lambda_{2} = \frac{x_{2}*d}{L}

\lambda_{2} = 0.45 m*\frac{d}{L}   (2)  

By entering equation (1) into equation (2) we have:

\lambda_{2} = 0.45 m* 1.033 \cdot 10^{-6} = 4.648 \cdot 10^{-7} m = 464.8 nm

Therefore, the second wavelength is 464.8 nm

I hope it helps you!          

3 0
3 years ago
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