Question

A 8.8 cm diameter circular loop of wire is in a 1.04 T magnetic field. The loop is removed from the field in 0.30 s . Assume that the loop is perpendicular to the magnetic field. Part A What is the average induced emf?

Answer 1

Answer:

0.021 V

Explanation:

The average induced emf (E) can be calculated usgin the Faraday's Law:

$E = - \frac{N*\Delta \phi}{\Delta t}$  

Where:

N = is the number of turns = 1  

ΔΦ = ΔB*A                                            

Δt = is the time = 0.3 s  

A = is the loop of wire area = πr² = πd²/4

ΔB: is the magnetic field = (0 - 1.04) T                    

Hence the average induced emf is:

$E = - \frac{\Delta B*A}{\Delta t} = - \frac{(0- 1.04 T) \pi (0.088 m)^{2}}{4*0.3 s} = 0.021 V$                      

Therefore, the average induced emf is 0.021 V.

I hope it helps you!