Predict the sign of ΔSo for the following reaction:

Chemistry

1 answer:

Sergio [31]2 years ago

8 0

Answer: Option (a) is the correct answer.

Explanation:

Entropy means the degree of randomness present within the molecules of an object.

When a substance is present in a solid state then its molecules are held together because of strong intermolecular forces of attraction.

As a result, molecules are not able to move freely and therefore, there will be no randomness.

But when a substance changes into liquid state then its molecules mover further apart from each other due to gain in kinetic energy. Hence, randomness increases.

On the other hand, when a substance moves from liquid to gaseous state then its molecules gain more kinetic energy due to which there will be high degree of randomness.

Therefore, as the products in the given reaction are present in liquid and gaseous state. So, this means that there has been an increase in entropy.

A decrease in entropy is represented by negative sign and an increase in entropy is represented by a positive sign.

Thus, we can conclude that the sign of $\Delta S_{o}$ for the given reaction is $\Delta S_{o}$ > 0.

You might be interested in

How many grams are there in 9.40*10^25 molecules of H2

IrinaVladis [17]

>4Dt. 1950 y fueron. 45Dys Imox x Na motu cues G.91 %10° mole cultes. 3) How many grams are there in 2.3 x 1024 atoms of silver? 2, 3x 10°tatoms x Imol.<

5 0

2 years ago

If the molecule could move upward without colliding with other molecules, then how high would it go before coming to rest? Give

tankabanditka [31]

The maximum height at which nitrogen molecule will go before coming to rest is 14 kilometers.

Given:

The nitrogen gas molecule with a temperature of 330 Kelvins is released from Earth's surface to travel upward.

To find:

The maximum height of a nitrogen molecule when released from the Earth's surface before coming to rest.

Solution:

The maximum height attained by nitrogen gas molecule = h
The temperature of nitrogen gas particle = T = 330 K

The average kinetic energy of the gas particles is given by:

$K.E=\frac{3}{2}K_bT\\\\K.E=\frac{3}{2}\times 1.38\times 10^{-23} J/K\times 330 K\\\\K.E=6.381\times 10^{-21} J$

The nitrogen molecule at its maximum height will have zero kinetic energy as all the kinetic energy will get converted into potential energy

The potential energy at height h = $P.E = 6.381\times 10^{-21} J$
Molar mass of nitrogen gas = 28.0134 g/mol
Mass of nitrogen gas molecule = m

$m= \frac{ 28.0134 g/mol}{6.022\times 10^{23} mol^{-1}}=4.652\times 10^{-23} g\\\\1g=0.001kg\\\\m=4.652\times 10^{-23}\times 0.001 kg\\\\=4.652\times 10^{-26} kg$

The acceleration due to gravity = g = 9.8 m/s^2
The maximum height attained by nitrogen gas molecule = h
The potential energy is given by:

$P.E=mgh$

$6.381\times 10^{-21} J=4.652\times 10^{-26} kg\times 9.8 m/s^2\times h\\\\h=\frac{6.381\times 10^{-21} J}{4.652\times 10^{-26} kg\times 9.8 m/s^2}\\\\h=13,996.6 m\\\\1 m = 0.001 km\\\\h=13,996.6 m=h=13,996.6\times 0.001 k m\\\\=13.9966 km \approx 14 km$