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2 years ago

Predict the sign of ΔSo for the following reaction:

Chemistry

1 answer:

Sergio [31]2 years ago

8 0

Answer: Option (a) is the correct answer.

Explanation:

Entropy means the degree of randomness present within the molecules of an object.

When a substance is present in a solid state then its molecules are held together because of strong intermolecular forces of attraction.

As a result, molecules are not able to move freely and therefore, there will be no randomness.

But when a substance changes into liquid state then its molecules mover further apart from each other due to gain in kinetic energy. Hence, randomness increases.

On the other hand, when a substance moves from liquid to gaseous state then its molecules gain more kinetic energy due to which there will be high degree of randomness.

Therefore, as the products in the given reaction are present in liquid and gaseous state. So, this means that there has been an increase in entropy.

A decrease in entropy is represented by negative sign and an increase in entropy is represented by a positive sign.

Thus, we can conclude that the sign of $\Delta S_{o}$ for the given reaction is $\Delta S_{o}$ > 0.

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How many moles of C2H2 are needed to react completely with 84 mol O2

Butoxors [25]

Balanced chemical equation:

2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

2 moles C2H2 ---------------- 5 moles O2
moles C2H2 ------------------ 84 moles O2

moles C2H2 = 84 * 2 / 5

molesC2H2 = 168 / 5 => 33.6 moles of C2H2

4 0

3 years ago

For each reaction below, use the drop-down menus to select which compound will form a precipitate. Note: It is possible that no

Dimas [21]

Answer:

1. Cadmium sulfide

2. Iron (III) hrydroxide

3. Barium carbonate

8 0

2 years ago

64.0 grams of Sulfur Dioxide absorbed 5.00 kJ of heat and immediately evaporated.

Airida [17]

Answer:

ewqdf

Explanation:

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8 0

3 years ago

What is the percent yield if 248.7 g of Cu is produced when 87 g of Al reacts with an excess

valkas [14]

Answer:

2.09 g Cu

Explanation:

First, we have to balance the equation:

3Al(s) + 3CuSO4(aq) = Al2(SO4)3(aq) + 3Cu(s)

Then we have to change grams of Al to mol:

1 mol Al = 26.98 g

1.37 g Al x (1 mol/26.98 g) = 0.051 mol

Then, we use the balanced equation to find the mol of Cu produced:

According to the equation:

3 mol Al produces 3 mol of Cu

3 mol Al = 3 mol Cu

So:

0.051 mol Al x (3 mol Cu/3 mol Al) = 0.051 mol Cu

This mol value is the theoric yield of the reaction.

Remember the equation for yield percent:

%Y = (Y real / Y theoric) x 100

Y theoric = 0.051 mol Cu

% Y = 67.4%

Let's replace these values on the equation and then fin Y real.

67.4 % = (Y real / 0.051) x 100

Y real = 0.033 mol Cu

So the real produced mol is 0.033 mol Cu.

Let's change these moles to grams:

1 mol Cu = 63.55 g

0.033 mol Cu x ( 63.55 g Cu/ 1 mol Cu) = 2.09 g Cu

If you want, watch the image attached is more clear the

mathematical procedure

Explanation:

6 0

2 years ago

Find the grams of iron in 79.2 g of Fe2O3.

Setler79 [48]

First you find the RFM (Relative Formula Mass) of Fe2O3
Fe2 = 56 x 2
= 112
O3 = 16 x 3
= 48

112 + 48 = 160

Moles = mass/RFM
   = 79.2/160
   =0.495

Then you rearrange the formula
Mass= moles x RFM
      = 0.495 x 112
      = 55.44 g
(To find mass of Iron have to use RFM of total iron in the substance example Fe2 ^^)

3 0

2 years ago