0.00011811023622 <span>i</span><span>nches</span>
B
. They are large and occur at shallow depths near the where the plates diverge.
Answer: 292.54g of Ag
Explanation:
Cu + 2AgNO3 →Cu(NO3)2 + 2 Ag
mass conc. Of Ag = n x molar Mass
Mass conc. Of Ag = 2 x 108 = 216g
From the equation,
63.5g of Cu produced 216g of Ag
Therefore, 86g of Cu will produce Xg of Ag. i.e
Xg of Ag = (86 x 216)/63.5 = 292.54g
Answer:
54.72 g
Explanation:
Mass = ?
Volume = 5.61 L
Pressure = 5.66 atm
Temperature = 311 K
The relationship between these equations is given by the ideal gas equation;
PV = nRT
where R = gas constant = 0.0821 atm L K-1 mol-1
n = PV / RT
n = 5.66 * 5.61 / (0.0821 * 311 )
n = 1.2436 mol
Number of moles = Mass / Molar mass
Mass = Number of moles * Molar mass = 1.2436 * 44 = 54.72 g