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2 years ago

What is the speed of a car that traveled 40.2km in 2 hours?

Chemistry

2 answers:

PolarNik [594]2 years ago

7 0

Answer:

20 km per hour

Explanation:

lawyer [7]2 years ago

5 0

Answer:

20.1 kmph

Explanation:

Since you usually need the answer to be a unit rate, where the denominator is always 1, you need to divide by whatever the numerator, the km, by the denominator, the hours. 40.2/2 is equal to 20.1.

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What volume (in L) of H2 would be collected at 22.0oC and a pressure of 713 torr if 2.65 g of zinc react according to the equati

ASHA 777 [7]

Answer: 83.74L

Explanation:

Temp. = 295K

P = 713torr = 0.938atm

Mass = 2.65g

PV = nRT

V = nRT/PV

n = Mass/Molar mass

Molar mass of Hydrogen gas = 1.00784*2= 2.0156g/mok

n = 2.65/2.0156 = 1.31469mol

V = 1.31469*0.08205*295/0.938

V = 83.74L

The volume = 83.74L

4 0

3 years ago

Which is an advantage of selling plant fertilizer as a powder rather than as a liquid?

elena55 [62]

Answer:A

Explanation: because i saw the sheet

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3 years ago

On the periodic table, periods are elements with similar

Vladimir [108]

Answer:

B.) Atomic Properties

can I have brainliest?

$Have\\a\\nice\\day$

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3 0

2 years ago

2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2

nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with $H_2$ to form $CH_4$ and $H_2O$ . balanced reaction is:

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

No. of moles of CO = 0.800 mol

No. of moles of $H_2$ = 2.40 mol

Volume = 8.00 L

Concentration = $\frac{Moles}{Volume\ in\ L}$

Concentration of CO = $\frac{0.800}{8.00} = 0.100\ mol/L$

Concentration of $H_2$ = $\frac{2.40}{8.00} = 0.300\ mol/L$

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

Initial 0.100 0.300 0 0

equi. 0.100 -x 0.300 - 3x x x

It is given that,

at equilibrium $H_2O (x)$ = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium $H_2$ = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium $CH_4$ = 0.0386 M

$Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}$

$Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90$

8 0

3 years ago

When the pH is high, what is tue concentration of hydrogen ions in a solution

joja [24]

Lowered cos the higher the ph the lower the hydrogen ions

5 0

3 years ago

Read 2 more answers