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puteri [66]
2 years ago
13

What is the speed of a car that traveled 40.2km in 2 hours?

Chemistry
2 answers:
PolarNik [594]2 years ago
7 0

Answer:

20 km per hour

Explanation:

lawyer [7]2 years ago
5 0

Answer:

20.1 kmph

Explanation:

Since you usually need the answer to be a unit rate, where the denominator is always 1, you need to divide by whatever the numerator, the km, by the denominator, the hours. 40.2/2 is equal to 20.1.

You might be interested in
A. Describe the molecule chlorine dioxide, CIO in terms of three possible resonance structures.
cupoosta [38]

Answer:

See explanation

Explanation:

The compound ClO2 has 19 valence electrons.  ClO2 is a bent molecule with tetrahedral electron pair geometry but has two  lone pairs of electrons. This is indicated by the presence of four electron pairs on the outermost shell of the central atom.

The molecule has an odd number of valence electrons, hence, it is generally regarded as a paramagnetic radical. None of the proposed Lewis structures for the molecule is satisfactory because none of them obeys the octet rule.

From the images attached, one can easily see that the electron dots around the oxygen and chlorine atoms does not satisfy the octet rule in all the resonance structures shown.

5 0
3 years ago
How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0
3 years ago
If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K and then I raise the pressu
mixas84 [53]

Answer:

The answer to your question is V2 = 29.6 l

Explanation:

Data

Pressure 1 = P1 = 12 atm

Volume 1 = V1 = 23 l

Temperature 1 = T1 = 200 °K

Pressure 2 = 14 atm

Volume 2 = V2 = =

Temperature 2 = T2 = 300°K

Process

1.- To solve this problem use the Combine gas law.

             P1V1/T1 = P2V2/T2

-Solve for V2

             V2 = P1V1T2 / T1P2

2.- Substitution

             V2 = (12)(23)(300) / (200)(14)

3.- Simplification

             V2 = 82800 / 2800

4.- Result

            V2 = 29.6 l

5 0
3 years ago
How many moles are 21.67 L of NH4CI?
Gnoma [55]

Answer:

0.967mole

Explanation:

Given parameters:

Volume of NH₄Cl  = 21.67L

Unknown:

Number of moles  = ?

Solution:

If we assume that the volume was taken at standard temperature and pressure,

 Then;

  Number of moles  = \frac{volume }{22.4L}  

 Number of moles  = \frac{21.67}{22.4}   = 0.967mole

8 0
3 years ago
The atomic number and the mass number of 18 and 40. Write the information conveyed by this statement.​
VashaNatasha [74]
There are 18 protons and electrons and 22 neutrons in the atom
8 0
3 years ago
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