Given:
0.607 mol of the weak acid
0.609 naa
2.00 liters of solution
The solution for finding the ph of a buffer:
[HA] = 0.607 / 2.00 = 0.3035 M
[A-]= 0.609/ 2.00 = 0.3045 M
pKa = 6.25
pH = 6.25 + log 0.3045/ 0.3035 = 6.25 is the ph buffer prepared.
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Answer:
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Answer:
get rid of waste material
Answer:
103.98 kpa
Explanation:
Pv= nRT
Where
P= pressure of the system=
n= number of moles= 3 moles
T= temperature= 250 K
Volume of the container= 60 liters
R= 0.0821L.atm/K.mol
Substitute the values
Pv= nRT
P= nRT/ V
= (3×0.0821×250)/60
= 1.026 Atm
1atm= 101325 Pascal
1.026 atm= X
= 103984 pasca
Convert to kilopascal
= 103984 pasca /1000
= 103.98 kpascal