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3 years ago

10

Dois automóveis A e B percorreram uma trajetória retilínea conforme as equações horárias Sa = 30 + 20t e Sb = 90 – 10t, sendo a

posição S em metros e o tempo t em segundos. No instante t = 0s, a distância, em metros, entre os automóveis era de:

1 answer:

Ray Of Light [21]3 years ago

4 0

Answer:

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Explanation:

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3 years ago

Which of the following results when a crest and trough meet?

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3 years ago

What is a circuit that only has one loop??

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3 years ago

An automatic clothing drier spins at 51.6 rev/min. If the radius of the drier drum is 30.5cm, how fast (in m/s) is the drier dru

Jlenok [28]

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1.648 m/s

Explanation:

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3 years ago

Objects with masses of 135 kg and a 435 kg are separated by 0.500 m. Find the net gravitational force exerted by these objects o

IrinaVladis [17]

Answer:

The net gravitational force on the mass is $1.27\times 10^{-5}$

Explanation:

We have by Newton's law of gravity the force of attraction between masses $m_{1},m_{2}$

$F_{att}=G\frac{m_{1}m_{2}}{r^{2}}$

Applying vales we get

Force of attraction between 135 kg mass and 38 kg mass is

$F_{1}=6.67\times 10^{-11}\frac{135\times 38}{(0.25)^{2}}\\\\F_{1}=5.47\times 10^{-6}N$

Force of attraction between 435 kg mass and 38 kg mass is

$F_{2}=6.67\times 10^{-11}\frac{435\times 38}{(0.25)^{2}}\\\\F_{2}=1.76\times 10^{-5}N$

Thus the net force on mass 38.0 kg is $F_{2}-F_{1}=1.76\times 10^{-5}-5.47\times 10^{-6}\\\\F_{2}-F_{1}=1.27\times 10^{-5}$

8 0

3 years ago