Answer: 1666J
Explanation:
Given that,
Mass of box (m) = 10kg
Total distance covered by box (h)
= (5m + 12m)
= 17m
work done on the box = ?
Work is done when force is applied on an object over a distance. Hence, the magnitude of work done on the box depends on its mass (m), distance covered (h), and acceleration due to gravity (g)
(g has a value of 9.8m/s²
i.e Work = mgh
Work = 10kg x 9.8m/s² x 17m
Work = 1666J
Thus, 1666 joules of work was done by the woman on the box.
Then the force will also be doubled
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Given:
ρ = 13.6 x 10³ kg/m³, density of mercury
W = 6.0 N, weight of the mercury sample
g = 9.81 m/s², acceleration due to gravity.
Let V = the volume of the sample.
Then
W = ρVg
or
V = W/(ρg)
= (6.0 N)/[(13.6 x 10³ kg/m³)*(9.81 m/s²)]
= 4.4972 x 10⁻⁵ m³
Answer: The volume is 44.972 x 10⁻⁶ m³
(1) The time of motion of the arrow is 0.25 s.
(2) The vertical height dropped by the arrow as it approaches the target is 0.31 m.
The given parameters:
- <em>Horizontal distance of the arrow, X = 20 m</em>
- <em>Horizontal speed of the arrow, v = 80 m/s</em>
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The time of motion of the arrow is calculated as follows;
The vertical height dropped by the arrow as it approaches the target is calculated as follows;
Learn more about time of motion of projectile here: brainly.com/question/1912408
