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8_murik_8 [283]
3 years ago
8

which of these solutions has the lowest freezing point? 0.25 m nacl 0.5 m nacl 1.0 m nacl 1.5 m nacl 2.0 m nacl

Chemistry
2 answers:
zloy xaker [14]3 years ago
6 0

Answer:

2.0 m nacl

Explanation:

Depression of freezing point is given by the equation:

ΔTf = m. Kf. i

where i is the Van't Hoff factor, m is the molality, and Kf is the freezing point depression constant.  

As per the formula, depression of freezing point is directly proportional to the molality. 2.0 m NaCl has the highest molaity and will have the maximum depression in freezing point. As  a result it will also have the lowest freezing point.  

Alinara [238K]3 years ago
4 0
The more particles (ions or molecules) that you can put into solution, the lower the freezing point. 

the answer is E. 2.0 M nacl
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For ethanol, propanol, and n-butanol the boiling points, surface tensions, and viscosities all increase. what is the reason for
Contact [7]
Moving from Ethanol through Propanol to Butanol the physical properties like boiling points, surface tension and viscosity increases because of the increases in intermolecular interactions between the molecules of given compounds.

Explanation:
                   Ethanol, propanol and butanol all have hydroxyl groups in common, means all have hydrogen bond intractions between their molecules. So, taking the hydrogen bonding interaction constant we are left with only the difference in the number of carbon atoms.
                    Butanol has the greatest physical properties than other two because it has four carbon atom chain. So, as we know the London Dispersion forces or Van der Waal forces increases with increase in molecular size and chain length of hydrocarbon.
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3 0
2 years ago
And with solution...
Tems11 [23]

Answer:

The answer to your question is: V = 6.93 L

Explanation:

Data

N₂ = 5.6 g

Volume of NH₃ = ?

                              14 g of N   ----------------  1 mol

                              5.6 g -----------------------   x

                             x = (5.6 x 1) / 14 = 0.4 mol of N

Reaction

                                N₂    +     3H₂    ⇒    2NH₃

                                1 mol of N₂   ----------------  2 moles of NH₃

                                0.4 mol of N₂ --------------   x

                               x = (0.4 x 2) / 1

                               x = 0.8 mol of NH₃

Formula

                 PV = nRT

P = 5200 torr = 6.84 atm

V = ?

n = 0.8

R = 0.082 atm L/ mol °K

T = 450°C = 723°K

Substitution

                     V = (0.8)(0.082)(723) / 6.84

                     V = 6.93 L

7 0
3 years ago
Which explains why carbon is a component of so many elements?
murzikaleks [220]
Carbon is a component of so many elements because <span>It can form stable compounds with other elements and also bond with them.</span>
5 0
3 years ago
3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen​
Morgarella [4.7K]

Answer:

Molec_{\ H_{tot}}=1.206x10^{25}molec

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

Thus, the total number of molecules turns out:

Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec

Regards.

6 0
3 years ago
What are the steps to balance a chemical equation?
aleksandrvk [35]

Answer:

Step 1: The Unbalanced Chemical Equation. The unbalanced chemical equation is given to you. ...

Step 2: Make a List. ...

Step 3: Identifying the Atoms in Each Element. ...

Step 4: Multiplying the Number of Atoms. ...

Step 5: Placing Coefficients in Front of Molecules. ...

Step 6: Check Equation. ...

Step 7: Balanced Chemical Equation.

Explanation:

5 0
3 years ago
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