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saw5 [17]
3 years ago
6

Four most common oxyanions of Iodine

Chemistry
2 answers:
nikitadnepr [17]3 years ago
8 0
HIO= Hypoiodous acid; IO-=Hypoiodite
HIO2= Iodous acid; IO2= iodite
HIO3=Iodic acid; IO3-= iodate
HIO4=Periodic acid; IO4-=Periodate
const2013 [10]3 years ago
6 0

Answer:

IO_4^-= Periodate\ ion

IO_3^-= Iodate\ ion

IO_2^-= Iodite\ ion

IO^-= Hypoiodite\ ion

Explanation:

Oxyanions:

Oxyanions are anions that have one or more oxygen atoms bonded to another elements is called oxyanions.

General formula of oxyanions are : A_xO_y^{z-}

Where, A represents an element and O represents oxygen atom.

Four most common oxyanions of Iodine are:

IO_4^-= Periodate\ ion

IO_3^-= Iodate\ ion

IO_2^-= Iodite\ ion

IO^-= Hypoiodite\ ion

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Answer:    A chemical process must occur and then changes between the state of the reactants and the state of the products can be determined

Explanation:  Enthalpy represents the sum of the energy of the system with the product of the pressure and volume of that system. As a thermodynamic property, it expresses the ability to release heat from the system. In fact, enthalpy  tells us how much heat and work has changed during the chemical reaction under constant pressure. When measuring, measurements of the difference in enthalpy between the two states of the system is performed, before and after the chemical reaction, since total enthalpy can not be measured. This measurement of the enthalpy change can tell us, for example, whether the heat was released from the system during the reaction, or the system absorbed the heat.

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3 years ago
C: Ms. Bakare has two bottles of sulfuric acid, X and Y. There is one litre of acid in each bottle.
umka2103 [35]

Acid of x bottle is highly reactive because solute is more and acid of y bottle is less reactive because solvent is more.

8 0
2 years ago
If you added 45,000 calories to water that was at 25 degrees C, and the ending temperature was 35 degrees C, how much water did
user100 [1]

<u>Answer:</u>

<em>4.5 L water we have in litres (L).</em>

<em><u></u></em>

<u>Explanation:</u>

Q=m\times c \times \Delta T

where

\Delta T = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0  cal/(g℃))  

m is the mass of water

Plugging in the values  

\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times\left(35^{\circ} \mathrm{C}-25^{\circ} \mathrm{C}\right)$\\\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}$\\\\$m=\frac{45000 \mathrm{cal}}{1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}}$\\\\$m=4500 \mathrm{g}$\\\\Density of water $=\frac{\text { mass }}{\text { volume }}$

So,

Volume of water = mass/density

\\\\=\frac{4500 \mathrm{g}}{\frac{1.09}{\mathrm{mL}}}=4500 \mathrm{mL}$$

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6 0
3 years ago
Magnesium oxide (MgO) forms when the metal burns in air. (a) If 1-25 9 of MgO contains 0.754 g of Mg, what is the mass ratio of
Vsevolod [243]

Answer:

Explanation:

a )

1.25 g MgO contains .754 g of Mg .Rest will be O

so oxide = 1.25 - .754 = 0.496 g

ratio of magnesium to oxide = .754/.496 = 1.52

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max2010maxim [7]

Explanation:

When solid cadmium sulfide reacts with an aqueous solution of sulfuric acid then the reaction will be as follows.

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Hence, ionic equation for this reaction is as follows.

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Therefore, net ionic equation for this reaction is as follows.

      CdS(s) + 2H^{+}(aq) \rightarrow Cd^{2+}(aq) + H_{2}S(g)

8 0
3 years ago
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