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user100 [1]
2 years ago
9

An 80kg astronaut traveled to the moon, where gravity is one-sixth (116) as

Physics
1 answer:
PIT_PIT [208]2 years ago
7 0

Answer:

Wmoon = 131 [N]

Explanation:

We know that the weight of a body is equal to the product of mass by gravitational acceleration.

Since we are told that the gravitational acceleration of the moon is equal to one-sixth of the acceleration of Earth's gravitation. Then we must multiply the value of Earth's gravitation by one-sixth.

w_{moon}=\frac{1}{6} *m*g\\w_{moon}=\frac{1}{6} *80*9.81\\w_{moon}=130.8 [N] = 131 [N]

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Find the minimum radius of a helium balloon that will lift her off the ground. the density of helium gas is 0.178 kg/m3, and the
marysya [2.9K]

Volume of balloon = \frac{4}{3} \pi r^{3}

Where r is the radius of balloon.

Here mass of woman = 68 kg

Mass of air displaced by a balloon with volume V = 1.29*V

Mass of helium inside balloon = 0.178*V

Total mass to be lifted by balloon = 68 +0.178*V

Buoyant force = 1.29V-0.178V=1.112V

So we have 1.112 V =  68+ 0.178*V

   0.934 V = 68

     V = 72.81 m^3

    \frac{4}{3} \pi r^{3}[/tex]= 72.81

     r = 2.59 m

So radius of helium balloon = 2.59 m

4 0
3 years ago
What are the four answers (in order) to fill in these blanks?<br><br> URGENT
ser-zykov [4K]

In a circuit, the electromotive force can be said to be the "source" of the "pushed electrons". This push then creates what is known as a current, which is the flow of electric charge through the circuit. This flow can be slowed down or restricted by a resistor, and this is also what can be harnessed in order to use electric power.

Explanation:

The electromotive force is the potential difference produced by the battery in the circuit. When the circuit is connected to the battery, this potential difference causes the electron to start moving towards the point at higher potential: in this sense, the electromotive force is said to be the "source" of the "pushed electrons".

This flow of electrons moving in the circuit is known as current.

Then, in the circuit, it is possible to place a piece of circuit with a smaller cross-section that restricts the flow of electrons: this component is known as resistor, and its property of restricting the flow of electron is known as resistance.

In a circuit, electromotive force (V), current (I) and resistance (R) are related by Ohm's law:

V=RI

Finally, when a current passes through a resistor, part of the electric energy is converted into thermal energy, and some power is dissipated through the resistor. The power dissipated is given by

P=I^2 R

This power can be harnessed, for instance, if the resistor is connected to a light bulb: the energy is transformed into heat and light, and so the light bulb turns on, providing illumination.

Learn more about current and resistance:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

3 0
3 years ago
Which object has the greatest inertia? *
____ [38]
One with greater mass (8kg)
4 0
3 years ago
Read 2 more answers
. A student times a car traveling a distance of 2 m. She finds that it takes the car 5 s to
AveGali [126]
No, the car travels 1 metre in 5s at the start which is 0.2m/s, while the second meter it travels one metre in 8 seconds which is 0.125 m/s, the speed changes therefore it is not constant during the two metres the car travels
3 0
3 years ago
Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of
Anna [14]

Given data:

* The extension of the steel wire is 0.3 mm.

* The length of the wire is 4 m.

* The area of cross section of wire is,

A=2\times10^{-6}m^2

* The young modulus of the steel is,

Y=2.1\times10^{11}\text{ Pa}

Solution:

The young modulus of the steel in terms of the force and extension is,

Y=\frac{F\times l}{A\times dl}

where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,

Substituting the known values,

\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}

Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.

7 0
1 year ago
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