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3 years ago

Please help....... what should I do in order to study effectively?

1 answer:

7 0

1) Find a good studying spot.
2) Stay Away From Your Phone or any other things that distract you.
3) Take a break after about 1-1 hour 30 minutes- break should be about 10 minutes.
4) make sure notes are complete for what you are revising for.
5) watch videos/ use class notes/ your own notes/ revision guides.
6) test yourself by answering exam style questions or by flash cards.

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Wat substance cannot be separated physically or chemically?

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Answer:

Anything that cannot be separated physically or chemically is an element.

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3 years ago

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Advantage fossil fuel

allochka39001 [22]

Answer:

The advantages of fossil fuels are that they are abundant and accessible, they provide a large amount of concentrated energy, they are relatively low cost and they can be transported relatively easily.

Explanation:

I got it from Google and Google is always right lol

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4 years ago

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Stainless steel is an alloy (mixture of metals) that many forks, knives, and spoons are made of. To make the stainless steel, a

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Add the weight of chromium, nickel and iron to get 25 pounds. Then divide the weight of chromium by the weight of the stainless steel to get 18%. Then find 18% of 25 g which is 4.5 g.

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3 years ago

The student is now told that the four solids, in no particular order, are barium chloride (BaCl2), sugar (C6H12O6), butanoic aci

boyakko [2]

Answer:

The student is now told that the four solids, in no particular order, are barium chloride (BaCl2), sugar (C6H12O6), butanoic acid (C3H7COOH), and sodium bromide (NaBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive to least conductive.

Explanation:

The given substances are:

barium chloride(BaCl2),

glucose(C6H12O6),

butanoic acid (C3H7COOH) which is a weak acid,

sodium bromide (NaBr).

The conductivity of a solution is proportional to the number of ions present in a particular solution.

1mol. of BaCl2 in water produces a total three mol. of ions.

$BaCl_2 (aq) -> Ba^2^+(aq) + 2Cl^-(aq)$

Gluocse is a covalent compound and it does not dissociate into ions in water.

So, it does not conduct electricity.

Butanoic acid is a weak acid. But due to the release of H+ ions it can conduct a very less amount of electricity.

NaBr is an ionic compound and in 1mol. of NaBr in water gives two mol. of ions.

NaBr (aq) -> Na+ (aq) + Br- (aq)

Hence, the order of conductivity among the given substances in aqueous solution is:

BaCl2 > NaBr > butanoic acid > glucose

4 0

3 years ago

Manganese metal can be prepared by the thermite process: 4Al(s) . 3MnO2(s). -->. 3Mn(l). 2Al2O3(s) molar masses, in g/mol: 26

nordsb [41]

Answer:

MnO2 is the limiting reactant

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

4Al(s) + 3MnO2(s) —> 3Mn(l) + 2Al2O3(s)

Step 2:

Determination of the masses of Al and MnO2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of Al = 26.98g/mol

Mass of Al from the balanced equation = 4 x 26.98 = 107.92g

Molar Mass of MnO2 = 86.94g/mol

Mass of MnO2 from the balanced equation = 3 x 86.94 = 260.82g

From the balanced equation above,

107.92g of Al reacted with 260.82g of MnO2 reacted.

Step 3:

Determination of the limiting reactant. This is illustrated below:

Let us consider using all the 203g of Al given to verify if there will be any leftover for MnO2. This is illustrated below:

From the balanced equation above,

107.92g of Al reacted with 260.82g of MnO2,

Therefore, 203g of Al will react with = (203 x 260.82)/107.92 = 490.61g of MnO2.

We can see that the mass of MnO2 that will react with 203g of Al is 490.61g which far greater than the 472g that was given. Therefore, it is not acceptable.

Now let us consider using all 472g of MnO2 given to verify if there will be any leftover for Al. This is shown below:

From the balanced equation above,

107.92g of Al reacted with 260.82g of MnO2,

Therefore, Xg of Al will react with 472g of MnO2 i.e

Xg of Al = (107.92 x 472)/260.82

Xg of Al = 195.30g

From the calculations above, we can see clearly that there are leftover for Al as 195.30g out of 203g reacted.

Therefore, MnO2 is the limiting reactant

3 0

4 years ago

Please help....... what should I do in order to study effectively?​

Please help....... what should I do in order to study effectively?