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3 years ago

WILL GIVE BRAINIEST

Mathematics

2 answers:

BabaBlast [244]3 years ago

8 0

Answer:

\frac{25}{100} \times x = 150

So,

x = \frac{150 \times 100}{25} = 600

Hank will use this equation.

Ans: A total of 600 pages are in the book.

Step-by-step explanation:

svlad2 [7]3 years ago

3 0

Answer:

Multiplication (150x4=600 25x4=100%)

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The area of triangle ABC is the amount of space on the triangle

The area of the triangle is 54.84 square units

<h3>How to determine the area of triangle ABC</h3>

Start by drawing the triangle (see attachment)

Next, calculate the measure of angle B using the following tangent ratio

$\tan(B/2) = \frac 34$

This gives

$\tan(B/2) = 0.75$

Take the arc tan of both sides

$B/2 = 36.87$

Multiply by 2

$B = 73.74$

Next, calculate the length of side AD using the following equation

$AD = \tan(B) * BD$

This gives

$AD = \tan(73.74) * 4$

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$Area = AD * BD$

This gives

$Area = 13.71 * 4$

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Hence, the area of the triangle is 54.84 square units

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Step-by-step explanation:

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Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function ()=−(+)^−

<em><u>Answer:</u></em>

vertex = (-4, -5)

Axis of symmetry = -4

use the (-4, -5) to find the minimum value

$Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5$

<em><u>Solution:</u></em>

Given function is:

$f(x) = (x+4)^2 - 5$

The equation in vertex form is given as:

$y = a(x-h)^2+k$

Where, (h, k) is constant

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h = -4

k = -5

Vertex is (-4 , -5)

Axis of symmetry : x co-ordinate of vertex

Thus, axis of symmetry = -4

The coefficient of x^2 is positive in given function.

Thus the vertex point will be a minimum

$Minimum\ value = f(\frac{-b}{a})$

$f(x) = x^2 + 8x + 16 - 5\\\\f(x) = x^2 + 8x + 11$

$f(x) = ax^2+bx+c$

On comparing,

a = 1

b = 8

$x = \frac{-b}{2a} = \frac{-8}{2 \times 1} = -4$

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Thus, use the (-4, -5) to find the minimum value

Domain and range

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The domain is the input values shown on the x-axis

The range is the set of possible output values f(x)

Therefore,

$Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5$

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