Is the process of bananas ripening a chemical change or a physical change? explain?

1 answer:

7 0

Bananas ripening is a chemical change. First, there is a change in color of peel from green to yellow then to brown. Second, there is a change in taste. You will notice a change in taste as the bananas ripen. They become sweeter and sweeter as they begin to ripen.

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An electrolytic cell is set up to plate Zr(s) from a solution containing Zr4 (aq). A current of 7.92 amps is run through this so

iren [92.7K]

The mass of Zr deposited in the process is 41.4 g.

<h3>What is electrolytic cell?</h3>

An electrolytic cell is a chemical cell which produces electrical energy by non-spontaneous chemical processes.

From the question;

Zr^4+(aq) + 4e ------> Zr(s)

We know that;

91 g of Zr is deposited by 4(96500) C

xg of Zr is deposited by (7.92 × 6.16 × 60 × 60) C

xg = 91 g × (7.92 × 6.16 × 60 × 60) C/4(96500) C

x g = 41.4 g

Learn more about electrolysis: brainly.com/question/12054569

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2 years ago

How to Calculate the de Broglie wavelength for each of the following ? a. an electron with a velocity 10.% of the speed of light

qaws [65]

H = planks constant
m = mass of the object 
u = velocity of the object 

h = 6.626 * 10^-34 J/s 
the mass of an electron is 9.12*10^-31 kg 
10% speed of light = 10% * 3*10^8 = 3*10^7 m/s, i dont have my graphing calc with me right now so i leave the technicalities up to you

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4 years ago

What feature of New York is located about 44°N, 74°W?

galben [10]

The Adirondacks is located there

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3 years ago

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If you could help me that would be awesome

elixir [45]

There are 3 significant figures. Significant numbers are the numbers that build up your total number. 1-9 always count, 0 only counts if it’s after another number. For example: 0,901 has 3 significant numbers as does 0,910. 9,10 also has 3. 0,09 has just 1.

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3 years ago

RATE LAW QUESTION !

vivado [14]

In general, we have this rate law express.:

$\mathrm{Rate} = k \cdot [A]^x [B]^y$
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4) by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation $\Delta \mathrm{Rate} = \Delta [B]^y$

$3.09 = (3)^y \implies y \approx 1$

To this point, $\mathrm{Rate} = k \cdot [A]^x [B]^1$

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for $\Delta \mathrm{Rate} = \Delta [A]^x$

$4= (2)^x \implies x = 2$

the rate law is

Rate = k·[A]²[B]

6 0

3 years ago