15 POINTS! Help.

Engineering

2 answers:

asambeis [7]3 years ago

7 0

Answer:

It is going to overload

Explanation:

<em>Hope this helps have a great day!</em>

IRISSAK [1]3 years ago

4 0

Answer: it would overload

Explanation:

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In a steady flow device, the properties of the system remains constant with time. a)True b) False

Leviafan [203]

Answer:

True

Explanation:

By definition of steady flow we have

$\frac{\partial f(x,y,z,t) }{\partial t}=0$

where f(x,y,z,t) is any property of the system under consideration

=> f(x,y,z,t) = constant

7 0

3 years ago

For an Na+—Cl- ion pair, attractive and repulsive energies EA and ER, respectively, depend on the distance between the ions r, a

Lunna [17]

Answer:

Explanation:

$\text{The curve of the plot}$ $\mathbf{E_A,E_R, \ and \ E_N}$ $\text{can be seen in the attached diagram below}$

$\text{From the plot}$ , $\mathbf{r_o = 0.2 4nm \ and \ E_o =-5.3 eV}$

$\mathbf{We \ knew \ that: E_N = E_A + E_R}$

$\mathtt{GIven \ E_A = \dfrac{-1.436}{r}\ \ \ , E_R = \dfrac{7.32 \times 10^{-6}}{r^n} \ \ and \ \ n=8 }$

$\mathtt{Then; E_N = -\dfrac{-1.436}{r}+ \dfrac{7.32\times 10^{-6}}{r^8}}$

$\mathtt{Also; r_o = \Big( \dfrac{A}{nB} \Big)^{\dfrac{1}{1-n}}} \\ \\ \mathtt{ r_o = \Big( \dfrac{1.986}{8 \times 7.32\times 10^{-6}} \Big)^{\dfrac{1}{1-8}}} \\ \\ \mathbf{r_o = 0.236 nm}$

$E_o = \dfrac{-1.436}{\Big[\dfrac{1.436}{8(732\times 10^{-6})}\Big]^{\dfrac{1}{1-8}}} + \dfrac{7.32 \times 10^{-6}}{\Big[ \dfrac{1.436}{8\times7.32 \times 10^{-6} } \Big]^{\dfrac{8}{1-8}}}$