Answer:
LAOD = 6669.86 N
Explanation:
Given data:
width
thickness 
crack length 2c = 0.5 mm at centre of specimen

stress intensity factor  =  k  will be

                    
we know that

    [c =0.5/2 = 2.5*10^{-4}]
          [c =0.5/2 = 2.5*10^{-4}]
K = 0.1724 Mpa m^{1/2} for 1000 load 
if then load will be
 then load will be

 
 



LAOD = 6669.86 N
 
        
             
        
        
        
Answer is an increase in pressure will cause an decrease in the pressure
        
             
        
        
        
Answer:
minimum electric power consumption of the fan motor is 0.1437 Btu/s
Explanation:
given data 
area = 3 ft by 3 ft
air density = 0.075 lbm/ft³
to find out
minimum electric power consumption of the fan motor
solution
we know that energy balance equation that is express as 
E in - E out  =  ......................1
    ......................1
and at steady state   = 0
 = 0 
so we can say from equation 1 
E in = E out 
so 
minimum power required is 
E in = W = m  =
 =  
  
put here value 
E in =   
  
E in =   
  
E in = 0.1437 Btu/s
minimum electric power consumption of the fan motor is 0.1437 Btu/s
 
        
             
        
        
        
Answer:
I know ship has stream line body 
 
        
             
        
        
        
Answer:
The tube surface temperature immediately after installation is 120.4°C and after prolonged service is 110.8°C
Explanation:
The properties of water at 100°C and 1 atm are:
pL = 957.9 kg/m³
pV = 0.596 kg/m³
ΔHL = 2257 kJ/kg
CpL = 4.217 kJ/kg K
uL = 279x10⁻⁶Ns/m²
KL = 0.68 W/m K
σ = 58.9x10³N/m
When the water boils on the surface its heat flux is:

For copper-water, the properties are:
Cfg = 0.0128
The heat flux is:
qn = 0.9 * 18703.42 = 16833.078 W/m²

The tube surface temperature immediately after installation is:
Tinst = 100 + 20.4 = 120.4°C
For rough surfaces, Cfg = 0.0068. Using the same equation:
ΔT = 10.8°C
The tube surface temperature after prolonged service is:
Tprolo = 100 + 10.8 = 110.8°C